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2 years ago

Here are four number cards.

Mathematics

1 answer:

yaroslaw [1]2 years ago

3 0

Answer:

a) 14

b) 514

Step-by-step explanation:

use number line for b

514 is 14 away from 500

485 is 15 away from 500

so 514 is closer to 500

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Evaluate 3x^2+5, when x= -5 and y= -9

dangina [55]

Step-by-step explanation:

$3x {}^{2} + 5$

$(3 \times - 5) {}^{2} + 5$

$- 15 {}^{2} + 5$

$225 + 5$

$230$

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2 years ago

there are eight girls competing in an ice skating competition,in how many ways can they finish in first,second, and third place?

Andreas93 [3]

8! - 5! = (8 * 7 * 6 * 5 * 4 * 3 * 2 * 1) - (5 * 4 * 3 * 2 * 1) = 8 * 7 * 6 = 336

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3 years ago

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Kimmi and her mom count 254 guests coming to the wedding. There are 9 tables at the wedding. How many guests sit at each table?

valkas [14]

Answer:

28 guests with 2 guests remaining

Step-by-step explanation:

254/9 = 28.2222222

so 28 remainder 2

hope this helps :) mark brainliest?

6 0

1 year ago

Simple, plz help! Need Plato answer

Nataly_w [17]

Factors of 121 are; 1,11, and 121. so it would be D.

7 0

2 years ago

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Situation:

Gala2k [10]

Answer:

5.5 days (nearest tenth)

Step-by-step explanation:

Given formula:

$\sf N=N_0e^{-kt}$

$\sf N_0$ = initial mass (at time t=0)
N = mass (at time t)
k = a positive constant
t = time (in days)

Given values:

$\sf N_0$ = 11 g
k = 0.125

Half-life: The time required for a quantity to reduce to half of its initial value.

To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

$\begin{aligned}\sf N & = \sf N_0e^{-kt}\\\\\implies \sf \dfrac{11}{2} & = \sf 11e^{-0.125t}\\\\\sf \dfrac{1}{2} & = \sf e^{-0.125t}\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf \ln e^{-0.125t\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t \ln e\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t(1)\\\sf t & = \sf \dfrac{\ln \left(\dfrac{1}{2}\right)}{-0.125}\\\\\sf t & = \sf 5.545177444...\\\\\sf t & = \sf 5.5\:\:days\:\:(nearest\:tenth)\end{aligned}$

Therefore, the substance's half-life is 5.5 days (nearest tenth).

Learn more about solving exponential equations here:

brainly.com/question/28016999

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1 year ago

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