This is volume, which is length times width time height.
4*9*5=180
The equation of a circle is (x-h)^2 + (y-k)^2 = r^2. Where "x" and "y" are variables, "h" and "k" are the coordinates of the center of the circle, and "r" is the length of the radius. It is given that the center of the circle is (-27, 120). So, h= -27 and k= 120. If the circle passes through the origin, we can assume that the origin is on the circle. Since a circle's radius is constant no matter where it is drawn/is, we can find the radius of the circle by finding the distance between the circle's center (-27, 120) and the origin, (0, 0). The distance formula is: d= √((x[2]-x[1])^2-(y[2]-y[1])^2). If the coordinates of the center of the circle are (x[2}, y[2]), then x[2]= -27 and y[2]= 120. Then, the origin is the (x[1], y[1]). So, x[1] = 0 and y[1] = 0. Plugging the numbers in we get: √((-27-0)^2-(120-0)^2). This gives us √(729+14400) = 123. So since the distance between the center of the circle and a point on the circle is 123 (units), then the radius has a value of 123.
Plugging all the numbers into the equation of a circle, we get: (x-(-27))^2+(y-120)^2=123^2.
Answer:
22.4 litres
Step-by-step explanation:
Reaction:
2Mg (s) + O2 (g) → 2 MgO (s)
From the reaction, we know that 2 moles of Mg (s) react with 1 mol of O2
STP conditions mean:
- absolute temperature of 273.15 K
- absolute pressure of 1 atm
Using the equation of state for ideal gases:
PV = nRT
where P is the absolute pressure, T is the absolute temperature, n are the moles, V is the volume, and R is the gas constant = 0.082 atm*L/(mol*K). Solving for V and replacing:
V = nRT/P
V = 1*0.082*273.15/1
V = 22.4 litres
The second answer since f goes inside g which gives u 5x^2
Answer:
4 root 3 i think
Step-by-step explanation: