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xenn [34]
3 years ago
13

amy earns $15 per week for doing chores around the house. write and solve an equation that determines how many weeks she needs t

o do chores to earn $105
Mathematics
2 answers:
anastassius [24]3 years ago
8 0

Answer:

7

Step-by-step explanation:

105 \div 15 is 7.

Furkat [3]3 years ago
4 0

Answer:

15 x 7 =105

Step-by-step explanation:( Amy needs to do chores for 7 weeks and she can earn 105 dollars) BRAINLIEST PLZZ

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Use the distance formula to find the perimeter of the triangle below. Round you answer to the nearest hundredth. ​
Murrr4er [49]

<u>jAlright, let's take this problem step-by-step</u>:

<u>What is the perimeter</u>:

 ⇒ all the side-lengths added up

    ⇒ <em>need</em> to find side-length using distance formula

                Distance_._. Formula=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

                         - (x₁,y₁): first point

                         - (x₂,y₂): second point

<u>Let's solve</u>:

  • Find length of <em>AC</em>

           ⇒ <em>first point</em>: (5,7)

<em>            ⇒ second point: </em>(3,3)

<em>            </em>Distance =\sqrt{(3-5)^2+(3-7)^2} =\sqrt{4+16} =\sqrt{20} =4.472

  • Find length of AB

          ⇒ <em>first point:</em> (5,7)

<em>           ⇒ second point:</em>(8,6)

<em>            </em>Distance=\sqrt{(8-5)^2+(6-7)^2} =\sqrt{9+1} =\sqrt{10}=3.162

  • Find length of BC

          ⇒<em> first point: </em>(8,6)

<em>           ⇒ second point: </em>(3,3)

<em>            </em>Distance = \sqrt{(3-8)^2+(3-6)^2} =\sqrt{25+9} =\sqrt{34}=5.831

<u>Now let's solve for the perimeter</u>:

  Perimeter = 4.472+ 3.126+ 5.831=13.429

<u>Answer: 13.43</u> (<em>rounded to the nearest hundredth)</em>

Hope that helps!

#LearnwithBrainly

<em>               </em>

5 0
2 years ago
R+2r=105 what is answer
Alik [6]

Answer:

If you're trying to solve for r. r=35

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

r+2r=105

(r+2r)=105(Combine Like Terms)

3r=105

3r=105

Step 2: Divide both sides by 3.

3r/3 = 105/3

r=35

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A. 1/3 is equivalemt to 0.3
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