Answer:
(8-(4*2)) / 1 =0
Step-by-step explanation:
(8-(4*2)) / 1 =0
(-3y^2 − 8) − (-5y^2<span> + 1)
= </span>-3y^2 − 8 + 5y^2<span> - 1
= 2</span>y^2 <span>- 9
answer is
</span>2y^2 - 9<span>
</span>
Answer:
As the lines are not intersecting nor parallel, they must be skew.
Step-by-step explanation:
Question is incomplete, we consider the nearest match available online.
Parametric equations of two lines are:
L₁ : x=4t+2 , y = 3 , z =-t+1
L₂: x=2s+2 , y= 2s+5 , z = s+1
If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.

If lines are intersecting then parametric coordinates must be equal for some value of t and s.

Hence the lines are not intersecting nor parallel, they must be skew.
Answer:
3x +19
Step-by-step explanation:
(9-6-4x+9)+(12+7x-5)
(12-4x)+(7+7x)
3x+19