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skelet666 [1.2K]
3 years ago
10

Point A is located at (2, 3) on the coordinate plane. Point A is reflected over the x-axis to form point B and over the y-axis t

o form point C. Then, point A is reflected over both axes to form point D. The four points become vertices of a quadrilateral. What is the most precise name for the quadrilateral formed, and how do you know?

Mathematics
1 answer:
Mademuasel [1]3 years ago
7 0

Answer:

Rectangle

Step-by-step explanation:

Well if point A is on (2,3) and you reflect it over the x axis point B would be located at (2,-3).

Then over the y axis point C would be located at (-2,-3), then reflecting that over the x axis point D is (-2,3)

<em><u>Points</u></em>

__________

A. (2,3)

B. (2,-3)

C. (-2,-3)

D. (-2,3)

__________

So graphing all these points we get a rectangle.

Because it has 4 sides that are 90 degrees and the sides opposite from each other are the same.

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Factor 36a^2x - b^2​
rodikova [14]

Answer:

36a2 - b2

Step-by-step explanation:

( 6a + b)( 6a - b)

36a2 - b2

6^2 a2 - b^2

x2 y2 = (xy)2

(6a)2 - b^2

(6a + b)(6a - b)

Hope that helps :)

8 0
3 years ago
Jerry randomly selected a point in the rectangle shown below. What is the probability the point he selected is in section A
vlabodo [156]
Jerry had a 3 in 10 chance or a 30 percent chance to hit area A randomly
5 0
3 years ago
skew-symmetric 3 x 3 matrices form as subspace of all 3 x 3 matrices and find a basis for this subspace.
Neporo4naja [7]

Answer:

a) ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

b) therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

Step-by-step explanation:

Given the data in the question;

W = { A| Air Skew symmetric matrix}

= {A | A = -A^T }

A ; O⁻ = -O⁻^T        O⁻ : Zero mstrix

O⁻ ∈ W

now let A, B ∈ W

A = -A^T       B = -B^T

(A+B)^T = A^T + B^T

= -A - B

- ( A + B )

⇒ A + B = -( A + B)^T

∴ A + B ∈ W.

∝ ∈ | R

(∝.A)^T = ∝A^T

= ∝( -A)

= -( ∝A)

(∝A) = -( ∝A)^T

∴ ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

A ∈ W

A = -AT

A = \left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]

= a\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] +b\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] +c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]

therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

8 0
3 years ago
The sum of two consecutive integers is 131. What are the integers?
Dahasolnce [82]
X, x+1
x+x+1=131
2x+1=131
2x=131-1=130
x=130÷2 = 65
the integers are 65 and 66
3 0
3 years ago
Please help meeeeeeeeee
rosijanka [135]

Step-by-step explanation:

1. 10-(2+3) = 5

2. 2x3 - 10 = -4

3. 3 x (4-2) = 6

4. (3+5) / 4 = 2

5. (5-2) x 3 = 9

6. (9-4) + 5 = 10

7 0
2 years ago
Read 2 more answers
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