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mixer [17]
4 years ago
5

Why do deserts appear in bands along earth's surface?

Geography
2 answers:
Svetlanka [38]4 years ago
7 0
Due to desertification and droughts

liraira [26]4 years ago
7 0
The Ferrel and Polar cells meet, creating areas of high pressure.
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Can yall help me with my 7 th grade science winter break homework pls
UkoKoshka [18]

So what is the question? We can help you if you show us.

5 0
4 years ago
Greeks propose the world is composed of what
mariarad [96]
The Ancient Greek purposed the world was composed of atoms.
3 0
3 years ago
what you think will be the greatest obstacle for the United States moving away from fossil fuels and toward greater use of renew
olasank [31]

Answer:

The Economic and capital costs , siting and strmission, market entry.

Explanation:

  • The greatest obstacle when moving from the fossil fuel to renewable energy is that of economic costs, as green or clean energy is reusable technology.
  • Availability of infrastructure is needed for the make more energy for the natural resources as compared to the fossil fuels are more easily to extract as compared to building solar and wind farms.
  • Like coals and natural gas accounts for 30 to 35 % of the market share as compared to the hydropower and other renewables.
7 0
4 years ago
Please answer this fast and here only​
Vaselesa [24]

Answer:

1) a) r_{R,I} = 1150\,m, b) r_{R,II} = 3400\,m, c) r_{R,III} = 2750\,m.

2) a) r_{R,I} = 45,2\,km, b) r_{R, II} = 28,15\,km, c) r_{R,III} = 51,8\,km.

Explanation:

The scale factor is defined by the following expression:

n = \frac{r_{S}}{r_{R}} (1)

Where:

n - Scale factor.

r_{S} - Scale distance, in centimetres.

r_{R} - Real distance, in centimetres.

1) If we know that n = \frac{1}{50000}, r_{S,I} = 2,3\,cm, r_{S,II} = 6,8\,cm and r_{S,III} = 5,5\,cm, then the actual distances in metres are:

r_{R,I} = \frac{r_{S,I}}{n}

r_{R,I} = \frac{2,3\,cm}{\frac{1}{50000} }

r_{R,I} = 115000\,cm

r_{R,I} = 1150\,m

r_{R,II} = \frac{r_{S,II}}{n}

r_{R,II} = \frac{6,8\,cm}{\frac{1}{50000} }

r_{R,II} = 340000\,cm

r_{R,II} = 3400\,m

r_{R, III} = \frac{r_{S, III}}{n}

r_{R,III} = \frac{5,5\,cm}{\frac{1}{50000} }

r_{R,III} = 275000\,cm

r_{R,III} = 2750\,m

2) If we know that n = \frac{1}{50000}, r_{S, I} = 90,4\,cm, r_{S, II} = 56,3\,cm and r_{S,III} = 103,6\,cm, then the actual distance in kilometres is:

r_{R,I} = \frac{r_{S,I}}{n}

r_{R,I} = \frac{90,4\,cm}{\frac{1}{50000} }

r_{R,I} = 4520000\,cm

r_{R,I} = 45,2\,km

r_{R,II} = \frac{r_{S,II}}{n}

r_{R,II} = \frac{56,3\,cm}{\frac{1}{50000} }

r_{R,II} = 2815000\,cm

r_{R, II} = 28,15\,km

r_{R, III} = \frac{r_{S, III}}{n}

r_{R,III} = \frac{103,6\,cm}{\frac{1}{50000} }

r_{R,III} = 5180000\,cm

r_{R,III} = 51,8\,km

4 0
3 years ago
According to our present theory of solar system formation, which of the following lists the major ingredients of the solar nebul
Misha Larkins [42]

Answer:

D. hydrogen compounds; hydrogen and helium gas; metal; rock

Explanation:

  • The solar system theory suggests the formation of the solar system comprised of 98% if the gases as the hydrogen and the helium and least of the metals and rock mass.
5 0
4 years ago
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