Question

The largest possible circle is cut out of a square whose side length is 6 feet. What will be the approximate area, in square feet, of the remaining board? ( where A=pie^r2 pie=3.14
8 ft2


16 ft2


24 ft2


36 ft2

Answer 1

Answer:

$8\ ft^{2}$

Step-by-step explanation:

we know that

The diameter of the largest possible circle is equal to the length side of the square

The approximate area of the remaining board is equal to the area of the square minus the area of the circle

so

$A=b^{2}-\pi r^{2}$

we have

$b=6\ ft$ ------> length side of the square

$r=6/2=3\ ft$ -----> the radius is half the diameter

$\pi =3.14$

substitute the values

$A=6^{2}-(3.14)(3)^{2}$

$A=7.74\ ft^{2}$

Round to the nearest whole number

$A=7.74=8\ ft^{2}$