The greatest common factor of all the coefficients is of 8.
<h3>What is the greatest common factor?</h3>
The greatest common factor between multiple terms is the largest value for which all terms are divisible.
In this problem, the equation is:
The terms are 16, 56 and 96. Hence, to find the gcf, we have to keep factoring them by prime factors while all can be factored by the same value, hence:
16 - 56 - 96|2
8 - 28 - 48|2
4 - 14 - 24|2
1 - 7 - 12
There are no terms by which both 7 and 12 are divisible, hence the procedure is stopped and:
gcf(16, 56, 96) = 2³ = 8.
You can learn more about the greatest common factor at brainly.com/question/26140769
Answer:
95%
Step-by-step explanation:
The Empirical rule, also the 68–95–99.7 rule, states that for a population that is approximately normal or symmetrical, nearly all of the data values will lie within three standard deviations of the mean;
68% of data values will fall within one standard deviation from the mean
95% of data values will fall within two standard deviation from the mean
99.7% of data values will fall within three standard deviation from the mean
From the graph given, we note that the weights 60 and 80 pounds fall within two standard deviations from the mean;
70 ± (2*5) = 70 ± 10 = (60, 80)
70 is the mean, 5 the standard deviation and 2 the number of standard deviations from the mean. From the Empirical rule we can conclude that the probability that a boxer weighs between 60 and 80 pounds is 95%
Answer:
6.47 x 10^-2
Step-by-step explanation:
Answer:
Step-by-step explanation:
ok
Answer:
Yes
Step-by-step explanation:
You can conclude that ΔGHI is congruent to ΔKJI, because you can see/interpret that there all the angles are congruent with one another, like with vertical angles (∠GIH and ∠KIJ) and alternate interior angles (∠H and ∠J, ∠G and ∠K).
We also know that we have two congruent sides, since it provides the information that line GK bisects line HJ, meaning that they have been split evenly (they have been split, with even/same lengths).
<u><em>So now we have three congruent angles, and two congruent sides. This is enough to prove that ΔGHI is congruent to ΔKJI,</em></u>
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