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3 years ago

The total rainfall in forks , washington, october was 8 3/8 in. in september ,60% less rainfall fell in October

1 answer:

6 0

Rainfall in October in Forks, Washington = 8 3/8 inches
= 67/8 inches
Percentage of rainfall that has fallen less in September in Forks, Washington = 60%
Let us assume the amount of rainfall in September in Forks, Washington = x
Then
100x/60 = 67/8
10x/6 = 67/8
5x/3 = 67/8
5x * 8 = 67 * 3
40x = 201
x = 201/40
= 5 1/40 inches
So the amount of rainfall in September in Washinton is 5 1/40 inches.

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Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

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Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

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Step-by-step explanation:

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Answer:

The correct option is;

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Step-by-step explanation:

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