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SpyIntel [72]
3 years ago
13

12 cot2(x) = 4 find all values of x in the interval [0, 2π] that satisfy the equation

Mathematics
1 answer:
Andreas93 [3]3 years ago
3 0
cot^2x = 4/12 \\

cot^2x = 1/3 \\

tan^2x = 3  \\

tan(x)= +- \sqrt{3} 


so,  x= \pi/3  \\ 
x = \pi - \pi/3 = 2\pi/3  \\
x = \pi + \pi/3 = 4\pi/3 \\
x = 2\pi - \pi/3 = 5\pi/3



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Answer:

No, the simplification is not done correctly. When multiplying

\frac{2}{3}\times-9 we should get -6 instead of -9.

the correct answer is 12k-8

Step-by-step explanation:

We need to tell if process was done correctly. If not, explain and correct the error by showing your own work.

The steps given are:

\frac{2}{3}  (6k - 9) + 8k - 2\\=4k - 9 + 8k - 2\\=12k - 11

No, the simplification is not done correctly. When multiplying

\frac{2}{3}\times-9 we should get -6 instead of -9.

Correcting the error:

\frac{2}{3}  (6k - 9) + 8k - 2\\=4k - 6 + 8k - 2\\=12k - 8

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function

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Answer:

P(z

And replacing the value obtained we got:

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And if we solve for a we got

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Step-by-step explanation:

Let X the random variable that represent the average home prices of a population, and for this case we know the distribution for X is given by:

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For this part we want to find a value a, such that we satisfy this condition:

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P(X   (b)

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And using the distribution for the sample mean we can do this:

P(X  

P(z

And replacing the value obtained we got:

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And if we solve for a we got

a=410000 -1.282*\frac{65000}{\sqrt{200}}=404107.68

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