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Aloiza [94]
3 years ago
7

The freshman class has 160 students. Each freshman must write three reports from a list of 12 novels that the teacher has assign

ed them to read. How many different combinations of novels can a freshman student choose to write reports on? 36 220 480
Mathematics
2 answers:
Novosadov [1.4K]3 years ago
5 0
220, because each student, can write 

12 and choose 3 possible combination of reports which is <span><span>n!</span><span><span>(n−k)</span>!k!</span></span>=220.  

a_sh-v [17]3 years ago
3 0

Answer with explanation:

Number of students in freshman class = 160

Total number of novels = 12

As, each freshman must write 3 reports , means selecting 3 novels out of 12 novels.

As,selection means order of choosing novels is not important.

So, we will apply rule of combinatorics here.

Selecting 3 novels out of 12 novels , is different combinations of novels that a freshman student  can choose to write reports on is given by

    _{3}^{12}\textrm{C}\\\\=\frac{12!}{(12-3)!3!}\\\\=\frac{12!}{9!\times3!}\\\\=\frac{12*11*10*9!}{9!*3*2*1}\\\\=11*10*2=220

Option B:220

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What is the solution to the system of equations y=-1/3x+9 and y=2/3x+12
amm1812

Answer:

{x = -3 , y = 10

Step-by-step explanation:

Solve the following system:

{y = 9 - x/3 | (equation 1)

{y = (2 x)/3 + 12 | (equation 2)

Express the system in standard form:

{x/3 + y = 9 | (equation 1)

{-(2 x)/3 + y = 12 | (equation 2)

Swap equation 1 with equation 2:

{-(2 x)/3 + y = 12 | (equation 1)

{x/3 + y = 9 | (equation 2)

Add 1/2 × (equation 1) to equation 2:

{-(2 x)/3 + y = 12 | (equation 1)

{0 x+(3 y)/2 = 15 | (equation 2)

Multiply equation 1 by 3:

{-(2 x) + 3 y = 36 | (equation 1)

{0 x+(3 y)/2 = 15 | (equation 2)

Multiply equation 2 by 2/3:

{-(2 x) + 3 y = 36 | (equation 1)

{0 x+y = 10 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{-(2 x)+0 y = 6 | (equation 1)

{0 x+y = 10 | (equation 2)

Divide equation 1 by -2:

{x+0 y = -3 | (equation 1)

{0 x+y = 10 | (equation 2)

Collect results:

Answer:  {x = -3 , y = 10

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m=0.05n-7
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