Answer:
2nd - (w - 5)(w + 5)
4th - (-4v - 9)(-4v + 9)
Step-by-step explanation:
1. The first option shows an expression multiplied by its opposite(x -1), so therefore, it does not show the difference of squares
2. The second option does show the difference of squares because it is in the form (a + b)(a - b)
3. The third option is just a square because the same expression is multiplied by itself.
4. The fourth option is the difference of squares because it is in the form (a + b)(a - b). a equals -4v and b equals 9 in this case.
5. The fifth option is not the difference of squares. No term in common in both expressions
6. The sixth option is just a square because the same expression is multiplied by itself.
In all, there are two options that are the difference of squares, the 2nd and 4th.
Answer:
The cost of wasted nitric acid is $187.02
Step-by-step explanation:
Since it is given that specific gravity of Nitric Acid is 1.42 Thus the density of nitric acid is
Now from the basic relation of mass volume and density we have
Since the mass of the nitric acid is given to be 5.112 kg = 5112 grams
Thus the volume of nitric acid is
Now we know that 1000 cubic centimeters euals 1 litrer
Thus the calculated volume in liters is
Thus the cost of acid spilled equals
Answer:
Below.
Step-by-step explanation:
f) (a + b)^3 - 4(a + b)^2
The (a+ b)^2 can be taken out to give:
= (a + b)^2(a + b - 4)
= (a + b)(a + b)(a + b - 4).
g) 3x(x - y) - 6(-x + y)
= 3x( x - y) + 6(x - y)
= (3x + 6)(x - y)
= 3(x + 2)(x - y).
h) (6a - 5b)(c - d) + (3a + 4b)(d - c)
= (6a - 5b)(c - d) + (-3a - 4b)(c - d)
= -(c - d)(6a - 5b)(3a + 4b).
i) -3d(-9a - 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b).
= (3d + 2c)(9a + 2b).
j) a^2b^3(2a + 1) - 6ab^2(-1 - 2a)
= a^2b^3(2a + 1) + 6ab^2(2a + 1)
= (2a + 1)( a^2b^3 + 6ab^2)
The GCF of a^2b^3 and 6ab^2 is ab^2, so we have:
(2a + 1)ab^2(ab + 6)
= ab^2(ab + 6)(2a + 1).
0.1389. 5 decided by 36 in a calc
52m^2= 2[(x-5)+(x)]. 52m^2= 2(2x-5). 52m^2=4x-10
