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3 years ago

4. Solve using elimination. 4x -3y = 9 3x +2y = 11

Mathematics

2 answers:

UNO [17]3 years ago

8 0

Answer: (3,1)

Explanation:

Natali5045456 [20]3 years ago

3 0

Answer:

x=3, y=1

Step-by-step explanation:

2(4x-3y=9) Multiply these two equations to cancel out the y using elimination

3(3x+2y=11)

8x-6y=18 Add these two equations to cancel out the y using elimination

9x+6y=33

17x=51 Solve for x

x=3

4(3)-3y=9 Plug in x=3 into the original equation

3y=3 Solve for y

y=1

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3 years ago

Please answer/do 3-7!! Whoever does it right, i will give brainlest! :) also, PLEASE FILL IT OUT EITHER ON PAPER/ PHONE etc. !!!

meriva

Answer:

3-7 is negitive 4 in your answer it's 3-7 = -4

Step-by-step explanation:

It's negitive four because if you subtract you will get 4 but since it's other way around. And if you do It, it will say that even if there is no negitive sign it won't change the problem because it's still the same problem.

1) 3 - 7

2) there are 3 ways to do this to get the answer:

1) 3/7

2) 7 + 3 - 4 + 3

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4) now check your answer by subtracting 3 and 7

5) then you get -4

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2 years ago

Read 2 more answers

Evaluate tan²0 for 0 = 60°. <br> 1/3 <br> 3/4 <br> 1 <br> 3

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Step-by-step explanation:

i Substituted the value ofthe variable into the equation and simplified it.

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2 years ago

Margin of error: 0.009; confidence level: 99%; p and a unknown

mafiozo [28]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.009}{2.58})^2}=20544.44$

And rounded up we have that n=20545

Step-by-step explanation:

Assuming this question: Use the data to find minium sample size required to estimate population proportion. Margin of error: 0.009, confidence level: 99%, p and q are unknown.

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by: