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ANEK [815]
3 years ago
9

True false) ther are five arrow keys on the keborad​

Computers and Technology
1 answer:
cluponka [151]3 years ago
5 0

Answer:

false, there's only 4

Explanation:

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You have just purchased a new USB drive that you want to use to troubleshoot the computers in your company as well as other netw
Masteriza [31]

Answer:

FAT32   is the correct answer to the given question        

Explanation:

FAT32 is a storage structure that is used for the purpose of the storage media. The main objective of the file system to manage the files on the hard drives, SSD, etc.

  • FAT32 is utilizing the 32-bit pieces of data for grouping of information in the hard disk.
  • The main advantage of the FAT32 file system it can format a USB drive that is recognized by all computer systems.
  • FAT32 is required less memory space on massive partitions of the hard disk.
8 0
3 years ago
Create a map using the Java map collection. The map should have 4 entries representing students. Each entry should have a unique
Angelina_Jolie [31]

Answer:

In Java:

import java.util.*;  

public class Main{

   public static void main(String[] args) {

       Map<String, String> students = new HashMap<>();

       students.put("STUD1", "Student 1 Name");

       students.put("STUD2", "Student 2 Name");

       students.put("STUD3", "Student 3 Name");

       students.put("STUD4", "Student 4 Name");

       for(Map.Entry m:students.entrySet()){  

           System.out.println(m.getKey()+" - "+m.getValue());    }  

}}

Explanation:

This creates the map named students

       Map<String, String> students = new HashMap<>();

The next four lines populates the map with the ID and name of the 4 students

<em>        students.put("STUD1", "Student 1 Name");</em>

<em>        students.put("STUD2", "Student 2 Name");</em>

<em>        students.put("STUD3", "Student 3 Name");</em>

<em>        students.put("STUD4", "Student 4 Name");</em>

This iterates through the map

       for(Map.Entry m:students.entrySet()){  

This prints the details of each student

           System.out.println(m.getKey()+" - "+m.getValue());    }  

4 0
3 years ago
I think the first one is correct but i'm not sure about the others. Can someone please help me?
bagirrra123 [75]

First option is correct. A Surge Suppressor protects when + More than 110 volts.

Explanation:

  • Sometimes the voltage of the connection quickly increases to a bigger higher value though for a very short period of time. This is called a spike.
  • A surge suppressor is a device inserted in the AC  utility line and telephone line to protect damage to electric devices from voltage spikes. They are a cheap way to protect the electric devices. They gives protection in amounts called joules.
  • A surge suppressor stops the peak AC voltage from going above 110 volts.

7 0
4 years ago
. the fact that a web app is written to be run within any of the standard
Evgen [1.6K]

The correct answer is C) ease of use.

The fact that a web app is written to be run within any of the standard browser and on any platform on which that browser operates is called "ease of use."

The ease of use concept indicates that the product is "amicable" or "friendly" to use by most people because it is not required andy technical knowledge to operate the product. In this case,  the app is written to be run within any of the standard browser and on any platform on which that browser operates, so it is "friendly" to operate bu most systems. App's companies and software companies created this "ease of use" concept for many of their products so they can sell most of them because people know they are easy to use and functional.

7 0
3 years ago
Write a Bash script that takes the name of a file or directory as an argument, 1. reports if it is a directory or a file, and if
Alla [95]

Answer:

see explaination

Explanation:

#!/bin/bash

mkdir sampleDir #I am just creating sample Directory

touch sampleFile #Creating sampleFile

echo 'Adding some information' >> sampleFile

cat sampleFile

echo "Listing the contents of the current directory:"

ls

file_size_kb=`du -k sampleFile | cut -f1` #Stores file size in KB, 1024KB = 1MB

echo $file_size_kb

if [ -d $1 ]; then

echo "It is a directory"

if [ -w $1 ]; then

echo "It has write permission"

fi

if [ -x $1 ]; then

echo "It has execute permission"

fi

if [ -r $1 ]; then

echo "It has read permission"

fi

if [ $file_size_kb -lt 1024 ]; then

echo "Small file"

elif [ $file_size_kb -gt 1024 ]; then

echo "Large file"

elif [ $file_size_kb -le 1024 && $file_size_kb -ge 1024 ]; then

echo "Medium file"

fi

elif [ -f $1 ]; then

echo "It is a file"

if [ -w $1 ]; then

echo "It has write permission"

fi

if [ -x $1 ]; then

echo "It has execute permission"

fi

if [ -r $1 ]; then

echo "It has read permission"

fi

if [ $file_size_kb -lt 1024 ]; then

echo "Small file"

elif [ $file_size_kb -gt 1024 ]; then

echo "Large file"

elif [ $file_size_kb -le 1024 && $file_size_kb -ge 1024 ]; then

echo "Medium file"

fi

fi

Check attachment for output and screenshot

4 0
3 years ago
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