The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.
Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11
Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
Answer:
e = 56
Step-by-step explanation:
Use cross multiplication.
28 * 14 = 7e
Simplify
392 = 7e
Divide each side by 7
e = 56.
(180(total angle measure of triangle)-50(EFG))/2(the other two angles have the same measure)=65
The angle CGE=180=CGF+EGF
180-65=CGF
115=CGF
It would be 3,000 as it is the next thousand. Since 2,641 is over 2,500 you can round to the next thousand 3,000
