Step-by-step explanation:

<h3>Answer:</h3>

Answer:
1=40
2=140
3=40
Step-by-step explanation:
We know on side
140 and side 2 are equal
1 and 3 are equal
So since 140 and 2 are equal
140*2=280
360 degrees total in any 4 sided shape
360-280=80
80/2=40



Because you can only add and subtract radicals with the same radicand,
you get 2

that is the simplified answer but if you want it in decimals, 2.022 is what you get.
Since the diagram represents parallel lines cut by a transversal line, the angles formed by these lines follow a series of rules. One of them is that corresponding angles are equal. Corresponding angles can be identified because they are located in the same position on different "crosses" formed by lines. In this case, angle x and the angle labeled 83° are corresponding angles and are therefore equal. We then know that angle x is 83° so choice B is correct.
I hope this helps.
Answer:
The area of the associated sector is
Step-by-step explanation:
step 1
Find the radius of the circle
we know that
The circumference of a circle is equal to

we have

substitute and solve for r


step 2
Find the area of the circle
we know that
The area of the circle is equal to

we have

substitute

step 3
Find the area of the associated sector
we know that
subtends the complete circle of area 
so
by proportion
Find the area of a sector with a central angle of 
