Ask question

Ask question

All categories

3 years ago

5

Solve the equation 30=-5(m+6)+m

1 answer:

notka56 [123]3 years ago

6 0

30 = -5(m+6) + m
30 = -5m - 30 + m
0 = -4m
0 = m

You might be interested in

Hi, I'm often really slow at learning math and my condition makes it harder, can someone help me?

NARA [144]

The answer: 0, 4/5 and 5

Explanation: first, we factor out 2x and get: 2x(5x^2-29x+20)=0

In order for this equation to be equal to zero, either 2x must equal to zero or (5x^2-29x+20) must equal to zero

Having said that, if:
2x = 0
X=0

If:
(5x^2-29x+20) = 0
X=4/6, x=5

7 0

2 years ago

Compute the weekly wages for the times given assuming a 40 hour week with time and a half for all overtime. Hourly wage: 10.50 a

kow [346]

you take 38 hours and multipy it by 10.50 is $399.00

3 0

3 years ago

In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study

DIA [1.3K]

Answer:

$z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055$

The p value can be calculated from the alternative hypothesis with this probability:

$p_v =2*P(Z>2.055)=0.0399$

And the best option for this case would be:

C. between 0.01 and 0.05.

Step-by-step explanation:

Information provided

$X_{1}=1642$ represent the number of smokers from the sample in 1995

$X_{2}=1415$ represent the number of smokers from the sample in 2010

$n_{1}=4276$ sample from 1995

$n_{2}=3908$ sample from 2010

$p_{1}=\frac{1642}{4276}=0.384$ represent the proportion of smokers from the sample in 1995

$p_{2}=\frac{1415}{3908}=0.362$ represent the proportion of smokers from the sample in 2010

$\hat p$ represent the pooled estimate of p

z would represent the statistic

$p_v$ represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

The statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374$

Replacing the info given we got:

$z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055$

The p value can be calculated from the alternative hypothesis with this probability:

$p_v =2*P(Z>2.055)=0.0399$

And the best option for this case would be:

C. between 0.01 and 0.05.

7 0

3 years ago

5÷5/6= please answer my question

solong [7]

Just like that? Any question, inbox. :p

6 0

3 years ago

And 43 pls thank would help a lot

Furkat [3]

43. 125 milliliters

45. 9 tsp

49. 6 tsp

4 0

3 years ago