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valentina_108 [34]
3 years ago
7

An + bn HELLLP WHAT IS THIS ANSWER

Mathematics
1 answer:
77julia77 [94]3 years ago
3 0

Answer:

I am completely lost

Step-by-step explanation:

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Find square root of the following numbers by long division method<br> 1).2025
erik [133]

Answer:

Hope this helps. Good luck

Step-by-step explanation:

6 0
3 years ago
What is one whole and three fourths plus five sixths plus one whole and one fourth
Naddika [18.5K]

Answer:

First of all  cant give u the anssswer i am srry but i can give u a hint u need to find eqivelent fractions for the denominators then u can add them

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in
Law Incorporation [45]

Answer:

(a) 900

(b) [567.35 , 1689.72]

(c) [23.82 , 41.11]

Step-by-step explanation:

We are given that a sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms i.e.;

Sample mean, xbar = 290      Sample standard deviation, s = 30  and  Sample size, n = 20

(a) Point estimate of the population variance is equal to sample variance, which is the square of Sample standard deviation ;

                         \sigma^{2}  =  s^{2} = 30^{2}

                          \sigma^{2}  = 900

(b) 90% confidence interval estimate of the population variance is given by the pivotal quantity of  \frac{(n-1)s^{2} }{\sigma^{2} } ~ \chi^{2} __n_-_1

P(10.12 < \chi^{2}__1_9 < 30.14) = 0.90 {At 10% significance level chi square has critical

                                           values of 10.12 and 30.14 at 19 degree of freedom}        

P(10.12 < \frac{(n-1)s^{2} }{\sigma^{2} } < 30.14) = 0.90

P(\frac{10.12}{(n-1)s^{2} } < \frac{1 }{\sigma^{2} } < \frac{30.14}{(n-1)s^{2} } ) = 0.90

P(\frac{(n-1)s^{2} }{30.14} < \sigma^{2} < \frac{(n-1)s^{2} }{10.12} ) = 0.90

90% confidence interval for \sigma^{2} = [\frac{19s^{2} }{30.14} , \frac{19s^{2} }{10.12}]

                                                   = [\frac{19*900 }{30.14} , \frac{19*900 }{10.12}]

                                                   = [567.35 , 1689.72]

Therefore, 90% confidence interval estimate of the population variance is [567.35 , 1689.72] .

(c) 90% confidence interval estimate of the population standard deviation is given by ;

       P(\sqrt{\frac{(n-1)s^{2} }{30.14}} < \sigma < \sqrt{\frac{(n-1)s^{2} }{10.12}} ) = 0.90

90% confidence interval for \sigma = [\sqrt{\frac{19s^{2} }{30.14}}   , \sqrt{\frac{19s^{2} }{10.12}}  ]

                                                 = [23.82 , 41.11]

Therefore, 90% confidence interval estimate of the population standard deviation is [23.82 , 41.11] .

7 0
3 years ago
What’s the volume and surface area
KiRa [710]

Surface area and volume are calculated for any three-dimensional geometrical shape. The surface area of any given object is the area or region occupied by the surface of the object. Whereas volume is the amount of space available in an object.

6 0
3 years ago
Please help me solve this!!
Mice21 [21]

Answer:

Abelito had the greater average speed

Step-by-step explanation:

Given

Bobby:

Distance =4\ miles

Time = 30\ minutes

Abelito

Distance = 10\ miles

Time = 48\ minutes

Required:

Who had a greater average speed

Average speed (S) is calculated as:

S = \frac{Distance}{Time}

We will make use of mph (miles per hour) as the unit of speed.

For Bobby:

S_B = \frac{4\ miles}{30\ minutes}

Convert minute to hour

S_B = \frac{4\ miles}{0.5\ hr}

S_B = 8mph

For Abelito

S_A = \frac{10\ miles}{48\ minutes}

Convert minute to hour

S_A = \frac{10\ miles}{0.8\ hr}

S_A = 12.5mph

By comparison: 12.5mph > 8mph

Hence: Abelito had the greater average speed

5 0
3 years ago
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