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2 years ago

HELP WITH THESE 4 QUESTIONS PLEASE ITS DUE IN A MINUTE

Mathematics

1 answer:

NikAS [45]2 years ago

8 0

So basically the answer is

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150 adults complete a survey 80 are female what's the ratio from men to female

Dafna11 [192]

80:70 WOULD BE THE RATION

3 0

2 years ago

Read 2 more answers

One more time!

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago

Determine the range of the graph above

kozerog [31]

Answer:

The range of the graph is:

-3 ≤ y ≤ 3

Hence, option (B) is correct.

Step-by-step explanation:

We know that the range of a function is the set of values of the dependent variable 'y' for which a function is defined.

From the given graph, it is clear that the graph goes down at y=-3 and then goes up to y=3 and then goes down again.

In fact, this indicates that the range of the graph lies between y=-3 to y=3

Therefore, the range of the graph is:

-3 ≤ y ≤ 3

Hence, option (B) is correct.

8 0

2 years ago

The function f(x)=2x-6 and g(x) is shown in the table

lesya692 [45]

Answer:

Multiply then add them and them that's your answer.

Step-by-step explanation:

5 0

2 years ago

Robert threw a rock off a bridge into the river. The distance from the rock to the river is modeled by the equation h=-16ť – 16t

cluponka [151]

Answer:

1.5 seconds

Step-by-step explanation:

h=-16t² – 16t+ 60

When the rock enter the water, the height is 0. ... h=0

0 = -16t² – 16t+ 60 = -4 * (4t² - 4t +15) = -4* (2t - 3) (2t +5)

2t-3=0 or 2t+5 = 0

t = 3/2 or t = -5/2 (time can't be negative)

t = 3/2 or 1.5

8 0

2 years ago