Answer:
a^2-3ab+2b^2
Step-by-step explanation:
(a-2b)(a-b)
a^2-2ab-ab+2b^2
a^2-3ab+2b^2
First, subtract 3 from both side (because they’re like terms) and then divide 2 from both sides to get x
Solution-:
3-2x=-5
-3 -3
-2x=-8
—- —-
-2 -2
X=4
;) thanks
Answer:
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Step-by-step explanation:
Answer: 0
Explanation:
1) Cosine trigonometric ratio definition:
cos (α) = adjacent-leg / hypotenuse
2) P (0,1) ⇒
- adyacent-leg = x-coordinate = 0
- opposite-leg = y-coordinate = 1
- hypotenuse = √[x² + y² ] = 1
3) Therefore, cos(α) = 0 / 1 = 0
Answer:
First question: Choice A
second question:Choice D
Third question: Choice c
Fourth question: Choise b
5th Question: choice b
