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Snowcat [4.5K]
3 years ago
13

Polygon MNOPQ is dilated by a scale factor of 0.8 with the origin as the center of dilation, resulting in the image M′N′O′P′Q′.

If M = (2, 4) and N = (3, 5), what is the slope of line M'N'?
A.√2
B.1
C.√3
D.√1/2
Mathematics
1 answer:
Goryan [66]3 years ago
4 0
M` = ( 0.8 * 2,  0.8 *4 ) = 0.8 * ( 2, 4 );
N` = ( 0.8 * 3, 0.8 * 5 ) = 0.8 * ( 3 , 5 ).  
The slope of line M`N` ( after dilation ):
m = Rise / Run = ( y 2 - y 1 ) / ( x 2 - x 1 ) =
= 0.8 * ( 5 - 4 ) / ( 0.8 ( 3 - 2 ) = 0.8 / 0.8 = 1
m = 1
Answer:
The slope of line M`N` is : B ) 1
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HELP PLEASE and show work
larisa86 [58]

Answer:

\boxed{\stackrel{\Large\frown}{PQS}\:= 222°}

Explanation:

Since \overline{PR} is a diameter, arc \stackrel{\Large\frown}{PQR}\:= 180°.

Given that \angle{SUR} = 42° is a subtended central angle by two diameters,

\stackrel{\large\frown}{RS} \:= 42°.

Using the rule of arcs, \stackrel{\Large\frown}{PQR} + \stackrel{\large\frown}{RS} \: = \: \stackrel{\Large\frown}{PQS} →

180° + \: 42° = \: \stackrel{\Large\frown}{PQS}

222° = \: \stackrel{\Large\frown}{PQS}

\stackrel{\Large\frown}{PQS} \: = \: 222°

3 0
3 years ago
We are in school 9 months out of the year. What percent of the year are we in<br> school?
Igoryamba

There are 12 months in a year.

Divide 9 by 12 then multiply by 100 to get the percentage.


9/12 = 0.75 x 100 = 75%

Answer: 75%

6 0
2 years ago
**URGENT** PLEASE HELP WILL GIVE BRAINLIEST
Gnoma [55]

Answer:

they are both 0 since they would not appear on a graph

Step-by-step explanation:

6 0
2 years ago
30 years ago zoe was 2/3 as old as luke, 18 years ago zoe was 5/6 as old as luke how old are they now
barxatty [35]

Based on the mathematical statements, Zoe is 56 years old and Luke is 66 years old, now

<h3>How to determine how old they are now?</h3>

From the question, we have the following statements that can be used in our computation:

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

Let their present ages be represented as

Zoe = x

Luke = y

So, we have the following representations

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

x - 36 = 2/3(y - 36)

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

x - 18 = 5/6(y - 18)

So, we have the following system of equations

x - 36 = 2/3(y - 36)

x - 18 = 5/6(y - 18)

Make x the subject in x - 18 = 5/6(y - 18)

x = 5/6(y - 18) + 16

Substitute x = 5/6(y - 18) + 16 in x - 36 = 2/3(y - 36)

5/6(y - 18) + 16 - 36 = 2/3(y - 36)

Open the brackets

5/6y - 15 + 16 - 36 = 2/3y - 24

Evaluate the like terms

5/6y - 35 = 2/3y - 24

Multiply through by 6

5y - 210 = 4y - 144

Evaluate the like terms

y = 66

Substitute y = 66 in x = 5/6(y - 18) + 16

x = 5/6(66 - 18) + 16

Evaluate

x = 56

Recall that

Zoe = x

Luke = y

So, we have

Zoe = x = 56

Luke = y = 66

Hence, they are 56 and 66 years, now

Read more about equations at

brainly.com/question/2476251

#SPJ1

5 0
10 months ago
HEEEELP <br> ABC m a-58<br> b-42<br> c-55<br> d-41
Savatey [412]
Your answer is going to be C
7 0
3 years ago
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