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4 years ago

11

mrs west is 14 years younger than her aunt. If mrs west's age in years is as much below 60 as her aunts age is over 40 how old i

s each

2 answers:

anygoal [31]4 years ago

6 0

60 - (x - 14) = x - 4060 - x + 14 = x - 40 74 - x = x - 40 74 = 2x - 40 114 = 2x 57 = x

Natali [406]4 years ago

4 0

So, the age of the aunt is 57 which is 17 years above 40 and the age of west is >>x-14=43 >> 43 which is 17 years below 60

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A dog sits at a corner of a square with side length 44 meters. the dog runs 10 meters along a diagonal toward the opposite corne

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Refer to the figure given below while reading the solution.

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2 years ago

What is the difference?

Serhud [2]

Answer:

The option $\frac{(x+5)(x+2)}{x^3-9x}$ is correct

The difference of the given expression is

$\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}$

Step-by-step explanation:

Given expression is $\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})$

To find the difference of the given expression as below :

$\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x^2-9)})-({\frac{x+1}{x^2-9})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x^2-3^2)})-({\frac{x+1}{x^2-3^2})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x-3)(x+3)})-({\frac{x+1}{(x-3)(x+3)})$

( using the formula $a^2-b^2=(a+b)(a-b)$ )

$=\frac{2x+5(x+3)-(3x+5)-x(x+1)}{x(x-3)(x+3)}$

$=\frac{2x^2+6x+5x+15-3x-5-x^2-x}{x(x-3)(x+3)}$ (adding the like terms)

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$=\frac{(x+5)(x+2)}{x^3-9x}$

Therefore $\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}$

Therefore the difference of the given expression is

$\frac{(x+5)(x+2)}{x^3-9x}$

Therefore option $\frac{(x+5)(x+2)}{x^3-9x}$ is correct

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3 years ago

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Aleks [24]

1. Collect like terms

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Final Answer:

0.7n + 1.5

4 0

4 years ago