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marta [7]
3 years ago
11

Please help and explain why!

Mathematics
1 answer:
scoundrel [369]3 years ago
4 0
1) The measures of the opposite angles of an inscribed quadrilateral are supplementary, add up to 180.

That means that angle ROP and angle RQP are supplementary.

We can add them and set them equal to 180 so that we can solve for x first.

∠ROP + RQP = 180
x + 17 + 6x - 5 = 180
7x + 12 = 180
7x = 168
x = 24

Now use the 24 for x and solve for the measure of angle ROP.

∠ROP = x + 17
∠ROP = 24 + 17
∠ROP = 41

The answer is A

2) The answer is A.

Hope this helps :)
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In the picture below, ABCD is a rectangle. If the area of triangle ABE is 40, what is the area of the triangle?
MariettaO [177]

Area of the rectangle: 112

Step-by-step explanation:

Picture is missing: find it in attachment.

The area of a triangle is given by

A=\frac{1}{2}bh

where

b is the length of the base

h is the height

For triangle ABE, we know that

A = 40 (area)

h = 8 (height)

So we can find the length of the base AE:

AE=b=\frac{2A}{h}=\frac{2(40)}{8}=10

Now we observe that the base of the rectangle, AD, is the sum of AE and DE, therefore:

AD=AE+DE=10+4=14

We also know the height of the rectangle AB is 8, and that the area of a rectangle is

A=bh

where b is the base and h the height. Therefore, the area of this rectangle is

A=bh=(AD)(AB)=(14)(8)=112

Learn more about area of figures:

brainly.com/question/4599754

brainly.com/question/3456442

brainly.com/question/6564657

#LearnwithBrainly

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