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Paraphin [41]
3 years ago
14

PLEAsE hELP :'000 20 POINTS

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
6 0

So, since the roots are -6, -2, 1, and 3, The graph MUST cross the X axis at these points.


The Top left graph is not correct, there is no root at 3

The top right graph is not correct ,no root at -6, or -2

The bottom Right Graph is incorrect, no root at 3 or 1


The Bottom Left graph is correct, since all roots are shown.

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Use the equation 459/x=85/100. then you cross multiply 459 and 100 to get 45900. after that you divide 45900 by 85 to get x=540
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Install (if you have a computer) and get familiar with Mathematica . Plot a Sin function over a range that is three times the pe
netineya [11]

Answer:

The period of the \sin function is 2\pi. Then three times this period is 6\pi.

Step-by-step explanation:

Using Mathematica you can use the command Plot as follows:

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The output is the graph shown below.

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Is the cross multiplication and . multiplication of vectors the same​
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no

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3 years ago
Which values are solutions for the intequality 5< y-8
Vanyuwa [196]

Answer:

y > 13

Step-by-step explanation:

Inequality graph:

6 0
3 years ago
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SOLVE FOR X??? <br><br><img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B3%7D%20%2B2%20%3D%5Cfrac%7Bx%7D%7B4%7D%2B3" id="TexFor
natima [27]

Answer:

\boxed{ \bold{ \boxed{ \sf{1. \:  \:  \:  \:  \: x = 12}}}}

\boxed{ \bold{ \boxed{ \sf{2. \:  \:  \:  \:  \: x = 3}}}}

Step-by-step explanation:

\sf{1. \:  \:  \:  \:  \frac{x}{3}  + 2 =  \frac{x}{4}  + 3}

Move x / 4 to left hand side and change its sign

Similarly, move 2 to right hand side and change it's sign

\longrightarrow{ \sf{ \frac{x}{3}  -  \frac{x}{4}  = 3 - 2}}

Take the L.C.M of 3 and 4

L.C.M of 3 and 4 = 12

\longrightarrow{ \sf{ \frac{x \times 4 - x \times 3}{12}  = 3 - 2}}

\longrightarrow{ \sf{ \frac{4x - 3x}{12}  = 3 - 2}}

\longrightarrow{ \sf{ \frac{x}{12}  = 3 - 2}}

Subtract 2 from 3

\longrightarrow{ \sf{ \frac{x}{12}  = 1}}

Do cross multiplication

\longrightarrow{ \sf{x  = 1 \times 12}}

\longrightarrow { \sf{x = 12}}

--------------------------------------------------------------------

\sf{2. \:  \:  \:  \: 3(4 + 2x) = 33 - x }

Distribute 3 through the parentheses

\longrightarrow{ \sf{12 + 6x = 33 - x}}

Move x to left hand side and change it's sign

Similarly, move 12 to right hand side and change it's sign

\longrightarrow{ \sf{6x +  x = 33 - 12}}

Collect like terms

\longrightarrow{ \sf{7x = 33 - 12}}

Subtract 12 from 33

\longrightarrow{ \sf{7x = 21}}

Divide both sides by 7

\longrightarrow{ \sf{ \frac{7x}{7}  =  \frac{21}{7} }}

Calculate

\longrightarrow{ \sf{x = 3}}

Hope I helped!

Best regards! :D

4 0
3 years ago
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