Who says V1=V2?
if we simplify we get
(2/3)pir₁³=12pir₂²
for V1 to equal V2
a.
solve for r₁ to find r₁ as a function of r₂
(2/3)pir₁³=12pir₂²
times 3/2 both sides and divide by pi
r₁³=18r₂²
cube root both sides
r₁=∛(18r₂²)
if solve for r₂
(2/3)pir₁³=12pir₂²
divide by 12pi both sides
(1/18)r₁³=r₂²
squer root both sides
√((1/18)r₁³)=r₂
double radius of pond which is r1
√((1/18)r₁³)=r₂
r₁ turns to 2r₁ to double radius
√((1/18)(2r₁)³)=r₂double
√(8(1/18)(r₁)³)=r₂double
(√8)(√((1/18)(r₁)³))=r₂double
√((1/18)r₁³)=r₂ so
(√8)(r₂)=r₂double
(2√2)(r₂)=r₂double
the radius of the tank is multipled by 2√2
Answer:
it is underfined because if you look closely there is no slope in the graph
Answer: 
Step-by-step explanation:
Answer:
this is not a real math equation.
Step-by-step explanation:
9514 1404 393
Answer:
y = -3x^2 -9x +30
Step-by-step explanation:
When a polynomial has a zero at x=p, it has a factor of (x -p). The factors of your quadratic are ...
f(x) = (x +5)(x -2)
At the point x=3, the value of this product is ...
f(3) = (3 +5)(3 -2) = (8)(1) = 8
In order for that value to be -24, it needs to be multiplied by a scale factor of -3. The quadratic you want is ...
y = -3(x +5)(x -2)
y = -3x^2 -9x +30 . . . . . standard form
