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3 years ago

Which tools were used by ancient mathematicians to make geometric constructions?

2 answers:

7 0

The tools that were used by ancient mathematicians to make geometric constructions are compasses and straightedges. A compass is a drawing instrument used to draw circles and arcs. The straightedges on the other hand is a tool to check on the accuracy of a straight line.

The answer is first choice.

max2010maxim [7]3 years ago

4 0

Answer:

Compasses and straightedges.

Step-by-step explanation:

The tool used by the ancient "Greek" mathematician to make geometric construction was the compasses and straightedges.

The compasses and straightedges can be used to combine to transfer the segment of the given length onto a line.

This can be done by only the following two steps:

Put point A and open it, till mark is visible on point B.
Liftoff and put the point on C and mark it on point D till its visible.

The compasses and straightedges are used to trace the part of the triangle.

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3 years ago

Given the following observed and expected data (total of 1000), using chi-squared calculate a p-value that corresponds with this

finlep [7]

Answer:

The answer is " $0.90>p>0.75.$ "

Step-by-step explanation:

$\text{Cinnabar vestigial} \ \ \ \ \ \ \ \ \ \ \ 384 \ \ \ \ \ \ \ \ \ \ \ 390 \ \ \ \ \ \ \ \ \ \ \ -6 36 \ \ \ \ \ \ \ \ \ \ \ 0.092308\\\\$

$roof \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 408 \ \ \ \ \ \ \ \ \ \ \ 390 \ \ \ \ \ \ \ \ \ \ \ 18 \ \ \ \ \ \ \ \ \ \ \ 324 \ \ \ \ \ \ \ \ \ \ \ 0.830769\\\\\text{Cinnabar vestigial roof} \ \ \ \ \ \ \ \ \ \ \ \ \ 63 \ \ \ \ \ \ \ \ \ \ \ \ \ 70\ \ \ \ \ \ \ \ \ \ \ \ -7 \ \ \ \ \ \ \ \ \ \ \ 49 \ \ \ \ \ \ \ \ \ \ \ 0.7\\\\\text{wild type} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 72 \ \ \ \ \ \ \ \ \ \ \ 70 \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ 0.057143\\\\$

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$Total \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1000 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2.965934$

Eight phenotypes were present.

Df is provided also by a number of phenotypes -1 The degree of freedom

$\to df = 8-1= 7$

For p-value 0,9, Chi-square is 2.83;

The p-value of 0.75 is 4.5. Chi-square

Chi-sqaure value is observed at 2.965.

That means 0.90>p-value>0.75.

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3 years ago

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pogonyaev

2x^3y^4. That how you do this

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3 years ago

The scale on a map is 1cm: 7km. If two cities are 15cm apart on the map, what is the actual distance between the cities?

Vitek1552 [10]

Answer:

105km

Step-by-step explanation:

1/7=15/x

So x=7*15

x=105

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3 years ago