(2, - 1); 4x + 3y = 5

In the diagram, what is the value of x ?

nexus9112 [7]

Your answer is 98. Is there a multiple choice?

8 0

2 years ago

Sophia exchanged 1000 U.S. dollars for the South African currency, which is called the rand. The exchange rate was 7.15 rand to

dolphi86 [110]

Part a:-

7.15 rands = 1 dollar

So we are going to MULTIPLY to find out how many rands there are going to be.

1000 × 7.15 = <span>7150

<span>So, 7150 rands is your answer.

Part b:-

To do this first we will DIVIDE.

6274 </span></span>÷ 7.15 ≈ <span>877.482.......

So, 6274 rands is ABOUT $878.

Par a:- 7150 rands

Part b:- about $878.

Hope I helped ya!!!!!</span>

3 0

3 years ago

How many helmets must the company make and sell to break even? helmets

klio [65]

The sale the company must make and sell to break even is;

B=600

<h3>How many helmets must the company make and sell to break even?</h3>

Generally, the equation for the break even is mathematically given as

In conclusion

B=y vertex/price of each

Therefore

B=15600/26

B=600

In conclusion, the company's break even is

B=600

CQ

A company plans to sell bicycle helmets for $26 each. The company's business manager estimates that the cost, y, of making x helmets is a quadratic function with a y-intercept of 8,400 and a vertex of (500, 15,900). How many helmets must the company make and sell to break even?

Read more about Arithmetic

brainly.com/question/22568180

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8 0

2 years ago

Read 2 more answers

Two angles whose sides are opposite rays are called ____ angles. Two coplanar angles with a common side, a common vertex, and no

Dimas [21]

Two angles whose sides are opposite rays are called vertical angles. Two coplanar angles with a common side, a common vertex, and no common interior points are called adjacent angles.

<h3>Further explanation </h3>

Adjacent Angles are two angles that share a common vertex, a common side, and no common interior points. They share a vertex and side, but do not overlap. The example is shown in the picture below.

Where ∠1 and ∠2 are adjacent angles, ∠ABC and ∠1 are NOT adjacent angles because ∠ABC overlaps ∠1.

Vertical Angles are two angles whose sides form two pairs of opposite rays (straight lines). Vertical angles are located across from one another in the corners of the "X" formed by the two straight lines. The example is shown in the picture below.

Where ∠1 and ∠2 are vertical angles, ∠3 and ∠4 are vertical angles, Vertical angles are not adjacent. ∠1 and ∠3 are not vertical angles (they are a linear pair) and Vertical angles are always equal in measure.

<h3>Learn more</h3>

Learn more about vertical angles brainly.com/question/2448393
Learn more about pair of angles brainly.com/question/1358595
Learn more about adjacent angles brainly.com/question/10557061

<h3>Answer details</h3>

Grade: 9

Subject: mathematics

Chapter: pair of angles

Keywords: vertical angles, adjacent angles, pair of angles, complementary angles, horizontal angles

7 0

3 years ago

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Separable differential equation <br> y’ln^2y+ysqrtx=0 y(0)=e

Maksim231197 [3]

By applying the theory of <em>separable ordinary differential</em> equations we conclude that the solution of the <em>differential</em> equation $\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0$ with y(0) = e is $y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}$ .

<h3>How to solve separable differential equation</h3>

In this question we must separate each variable on each side of the equivalence, integrate each side of the expression and find an <em>explicit</em> expression (y = f(x)) if possible.

$\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0$

$(\ln y)^{2}\,dy = -y \cdot \sqrt{x}\, dx$

$-\frac{(\ln y)^{2}}{y}\, dy = \sqrt{x} \,dx$

$-\int {\frac{(\ln y)^{2}}{y} } \, dy = \int {\sqrt{x}} \, dx$

If u = ㏑ y and du = dy/y, then:

$-\int {u^{2}\,du } = \int {x^{\frac{1}{2} }} \, dx$

$-\frac{1}{3}\cdot u^{3} = \frac{2\cdot x^{\frac{3}{2} }}{3} + C$

$u^{3} = -2\cdot x^{\frac{3}{2} } + C$

$(\ln y)^{3} = - 2\cdot x^{\frac{3}{2} } + C$

$C = (\ln e)^{3}$

$C = 1$

And finally we get the <em>explicit</em> expression:

$\ln y = \sqrt [3]{-2\cdot x^{\frac{3}{2} }+ 1}$

$y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}$

By applying the theory of <em>separable ordinary differential</em> equations we conclude that the solution of the <em>differential</em> equation $\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0$ with y(0) = e is $y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}$ .

To learn more on ordinary differential equations: brainly.com/question/14620493

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6 0

2 years ago