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3 years ago

Classify scatter plot

Mathematics

2 answers:

lys-0071 [83]3 years ago

4 0

Answer:

the answer is c. no relationship

KengaRu [80]3 years ago

3 0

C, no relationship is the answer

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What cross section shape is formed when the figure is cut as shown?

kirza4 [7]

Answer:

Triangle

Step-by-step explanation:

7 0

2 years ago

The following results come from two independent random samples taken of two populations.

photoshop1234 [79]

Answer:

$(a)\ \bar x_1 - \bar x_2 = 2.0$

$(b)\ CI =(1.0542,2.9458)$

$(c)\ CI = (0.8730,2.1270)$

Step-by-step explanation:

Given

$n_1 = 60$ $n_2 = 35$

$\bar x_1 = 13.6$ $\bar x_2 = 11.6$

$\sigma_1 = 2.1$ $\sigma_2 = 3$

Solving (a): Point estimate of difference of mean

This is calculated as: $\bar x_1 - \bar x_2$

$\bar x_1 - \bar x_2 = 13.6 - 11.6$

$\bar x_1 - \bar x_2 = 2.0$

Solving (b): 90% confidence interval

We have:

$c = 90\%$

$c = 0.90$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.90$

$\alpha = 0.10$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.10/2}$

$z_{\alpha/2} = z_{0.05}$

The z score is:

$z_{\alpha/2} = z_{0.05} =1.645$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.645 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.645 * \sqrt{0.3306}$

$2.0 \± 0.9458$

Split

$(2.0 - 0.9458) \to (2.0 + 0.9458)$

$(1.0542) \to (2.9458)$

Hence, the 90% confidence interval is:

$CI =(1.0542,2.9458)$

Solving (c): 95% confidence interval

We have:

$c = 95\%$

$c = 0.95$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.95$

$\alpha = 0.05$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.05/2}$

$z_{\alpha/2} = z_{0.025}$

The z score is:

$z_{\alpha/2} = z_{0.025} =1.96$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.96 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.96* \sqrt{0.3306}$

$2.0 \± 1.1270$

Split

$(2.0 - 1.1270) \to (2.0 + 1.1270)$

$(0.8730) \to (2.1270)$

Hence, the 95% confidence interval is:

$CI = (0.8730,2.1270)$

8 0

3 years ago

Suppose that X represents for the number of fishes caught on a certain day at a Michigan lake, and there is no available informa

lisov135 [29]

Answer:

sorry i cant cick out plz dont report my moused died plzzzzzz

Step-by-step explanation:

6 0

3 years ago

What is 8/3 times 12/5

Over [174]

Answer: 6.4 In decimal form. 32/5 in fraction form.

Step-by-step explanation:

So first times 8 by 12 which is 96

then, 3 times 5 which is 15

Simplify to 32/5

8 0

3 years ago

Read 2 more answers

By visiting homes door-to-door, a municipality surveys all the households in 31 randomly-selected neighborhoods to see how resid

monitta

Answer:

Cluster Sample

Step-by-step explanation:

Sometimes, a survey may involve people in a widespread geographical location. Taking samples from all part of the location may involve higher cost and even difficulty in accessing the whole area. Researchers therefore use a type of sampling method that help in overcoming this difficulty and still get results that can be used to judge the whole population.

This type of sampling is called cluster sampling. Cluster sampling involves sharing your population into clusters and randomly selecting two or more of the clusters. The researcher then samples from only the selected clusters.

In the question above, the population is already shared into clusters, in the form of neighbourhoods. The municipality then randomly selected 31 neighbourhoods out of the whole neighbourhoods in the city, just like in cluster sampling, then samples from only the selected neighbourhood. This is why the selected samples are cluster samples.

6 0

3 years ago