
If two similar waves are traveling in the same medium, then they have same wave velocity. so we can infer that

Now, as per the formula ~ we know that :

Now, we can write it as :

And it's also given that frequency of wave A is 3 times that of frequency of wave B.
So, let's add the relation to our equation ~



So, choice C is correct ~
Answer:
hauaidi
Explanation:
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<span>Tom realizes as she states this that Daisy is saying that she loves Gatsby. As the text puts it: She had told him that she loved him and Tom Buchanan saw. ... Daisy wants Tom to know she is in love (or at least thinks she is) with Gatsby and knows how to communicate this to her husband.</span>