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3 years ago

What will you get if you cut a triangle perpendiculary

Mathematics

2 answers:

o-na [289]3 years ago

8 0

Answer:

Two right triangles

Step-by-step explanation:

You will get two right triangles, if you cut a triangle perpendicularly through one vertex.

swat323 years ago

3 0

Answer:

2 triangles ?

Step-by-step explanation:

sorry if i got this wrong, when you cut it through the middle connecting the ends it give you two triangles?

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What system of equations is shown on the graph below?

erma4kov [3.2K]

Answer:

The equation of the line passing through the points (-2,0) and (0,-4)

$\frac{y - y1}{x - x1} = \frac{y2 - y1}{x2 - x1}$

$\frac{y - 0}{x - ( - 2)} = \frac{ - 4 - 0}{0 - ( - 2)} = \frac{ - 4}{2} = - 2$

$y = - 2(x + 2) \\ y = - 2x - 4$

$2x + y = - 4$

The equation of the line passing through the points (0,-2) and (4,0)

$\frac{y - y1}{x - x1} = \frac{y2 - y1}{x2 - x1} \:$

$\frac{y - ( - 2)}{x - 0} = \frac{0 - ( - 2)}{4 - 0}$

$\frac{y + 2}{x} = \frac{1}{2}$

$x - 2y = 4$

Option B

x minus 2 y = 4 and 2 x + y = negative 4

4 0

3 years ago

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MARIA WALKED 4.035 KILOMETERES. WHAT IS 4.035 WRITTEN IN AS EXPANDED FORM ?

notka56 [123]

Here's my interpretation: 4 whole km, plus zero tenths of a km, plus 3 hundredths of a km, plus 5 thousandths of a km.

4 0

3 years ago

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Find the rate of decay of the function b(x)=4(0.006)^x Enter your answer as a percent

yuradex [85]

The answer is .6 percent

6 0

2 years ago

Read 2 more answers

PLEASE HELP ME. THANKS!!!

Veronika [31]

Cos(x) = sin(x + 20o) Use the double cos angle formula

Cos(x) = sin(x)*cos(20) + cos(x)*sin(20) Divide through by cos(x). Tanx = sin(x)/cos(x)

1 = tan(x)*cos(20) + sin(20) Subtract sin(20) from both sides.

1 - sin(20) = tan(x)*cos(20) Calculate the value of 1 - sin(20)

0.65798 = tan(x) * 0.939692 Divide by cos(20)

tan(x) = 0.65795/0.939692

tan(x) = 0.70021 Take the inverse of 0.7) = tan(x)

x = tan-1(0.70021)

x = 35 degrees as expected.

Problem Two

The easiest way to do this is to pick random values and try it. The two acute angles are complementary. So 25 and 65 are random enough.

Let A = 25

Let C = 65

Tan(25) = sin(25)/sin(65) ; tan(25) = 0.4663.

sin(25)/sin(65) = 0.4663 Answer

Sin(90 - C) = Sin(A)

Tan(90 - A) = Tan(C)

So the question becomes Cos(A) = Tan(C) / sin(A)

Cos(25) = Tan(65)/Sin(25)

0.906 = ? 5.07 This statement isn't true.

Sin(65) = Cos(25)/Tan(65)

.906 = 0.4226 C is not the correct answer.

D isn't true. The tan does not relate that away. You can find it for yourself.

Cos(A) = Tan(C) You should get 0.906 = 2.14

Sin(C) = Cos(A) / Tan(A) I'll leave you to show this is wrong.

Problem 3

The diagram below is for this problem. Cos(x) = 50/100 = 0.5

x = cos-1(0.5)

x = 60 degrees.

Part 2

Sin(60) = opposite / hypotenuse

opposite = sin(60) * hypotenuse

opposite = 86.61 Be sure and round this to whatever the question says to round it to.

4 0

2 years ago

WILL GIVE BRAINLIEST

stira [4]

The air force plane travelled for a total of 6.9 hours.

SOLUTION: 

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph. A cargo plane left sometime later flying in the same direction at an average speed of 207 mph. After flying for 5.3 hours the cargo plane caught up with the Air Force plane.

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, $\text { distance travelled }=\text { speed } \times \text { time }$

For air force plane $\rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }$

$\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }$

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, $159 \times \text { time taken by air force plane }=207 \times 5.3$

$\Rightarrow =\frac{207 \times 5.3}{159}$

$\Rightarrow =\frac{1097.1}{159}$

Time taken by air force plane = 6.9 hrs

6 0

3 years ago