We know area of triangle = 
In triangle ABC , AB is the base and BC is the height
Now we find the distance between A and B
Distance formula is 
A(0,3), B(7,3)
Distance AB = 
=
= 7
B(7,3), C(7,7)
Distance BC = 
=
= 4
area of triangle = 
area of triangle = 
=
= 14 
Attached solution and work.
The answer is: x² – 6x + 9 = 0 .
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Explanation:
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Given: (x – 3)² = 0 ; write as: general form: "ax² + bx + c = 0"; a ≠ 0 .
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Note: </span>(x – 3)² = (x – 3)(x – 3) = x² – 3x – 3x + 9 = x² – 6x + 9 ;
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Rewrite: (x – 3)² = 0 ; →
as: x² – 6x + 9 = 0 ; which is our answer.
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→ x² – 6x + 9 = 0 ; is in "general form", or "standard equation format"; that is: " ax² + bx + c = 0 "; (a ≠ 0) ;
→ in which:
a = 1 (implied coefficient, since anything multiplied by "1" is that same value);
b = -6;
c = 9
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Simplified: x^3+5x^2-2x+1
in standard form: x^3+5x^2-2x+1
Answer:
108 pens
Step-by-step explanation:
48/4=x/9
4x=432
x=108