Answer:
Step-by-step explanation:
Given that customers arrat a service window according to a poisson process with an average of 0.2 per minute
= 12 per hour.
a) the probability that the time between two successive arrivals is less than 6 minutes
= For one hour more than 60/6 =10 customers arrive.
P(X>10) = 0.6528
b) Prob that there will be exactly three arrivals during a given 10-minute period
P(x=3) for average 2
= 0.1804
<u>Part</u><u> </u><u>(</u><u>a</u><u>)</u>

<u>Part</u><u> </u><u>(</u><u>b</u><u>)</u>

Y = 3x + 4
y = -x - 4
3x + 4 = -x - 4
3x + x = -4 - 4
4x = -8
x = -8/4
x = -2
y = 3x + 4
y = 3(-2) + 4
y = -6 + 4
y = -2
solution is (-2,-2) <==