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3 years ago

Please help!! ill give BRAINLIEST!!!

Mathematics

1 answer:

ella [17]3 years ago

6 0

Answer:

2. x=5.7

4. AC=7

steps :

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How do i express x^2-3x into the form of (x-m)^2+n. I will give brainliest to correct answer

mel-nik [20]

Step-by-step explanation:

let's simply do the multiplications and then compare with the original.

(x-m)² + n

right ?

or is it

${(x - m)}^{2 + n}$

let's go for the first.

x² - 2mx + m² + n = x² - 3x

-2mx + m² + n = -3x

fun there we see two things :

-2m = -3

m = 3/2

and

m² + n = 0

(3/2)² = -n

9/4 = -n

n = -9/4

so our transformed expression looks like

(x - 3/2)² - 9/4

7 0

3 years ago

Determine whether the given system has a unique solution, no solution, or infinitely many solutions.

victus00 [196]

Answer:

The system has no solution.

Step-by-step explanation:

To find the solution to this system of linear equations

$\left\begin{array}{ccccc}-3x_1&+x_2&-2x_3&=&8&\\x_1&+5x_2&-x_3&=&4&\\-x_1&+11x_2&-4x_3&=&1&\end{array}\right$

First, state the problem in matrix form, this means, extracting only the numbers, and putting them in a box.

$\left[ \begin{array}{ccc|c} -3 & 1 & -2 & 8 \\\\ 1 & 5 & -3 & 4 \\\\ -1 & 11 & -4 & 1 \end{array} \right]$

This is called an augmented matrix. The word “augmented” refers to the vertical line, which we draw to remind ourselves where the equals sign belong

Next, transform the augmented matrix to the reduced row echelon form with the help of Row Operations.

Row Operation 1: multiply the 1st row by -1/3

$\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 1 & 5 & -1 & 4 \\\\ -1 & 11 & -4 & 1 \end{array} \right]$

Row Operation 2: add -1 times the 1st row to the 2nd row

$\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & \frac{16}{3} & - \frac{5}{3} & \frac{20}{3} \\\\ -1 & 11 & -4 & 1 \end{array} \right]$

Row Operation 3: add 1 times the 1st row to the 3rd row

$\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & \frac{16}{3} & - \frac{5}{3} & \frac{20}{3} \\\\ 0 & \frac{32}{3} & - \frac{10}{3} & - \frac{5}{3} \end{array} \right]$

Row Operation 4: multiply the 2nd row by 3/16

$\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & \frac{5}{4} \\\\ 0 & 0 & 0 & -15 \end{array} \right]$

Row Operation 5: add -32/3 times the 2nd row to the 3rd row

$\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & \frac{5}{4} \\\\ 0 & 0 & 0 & -15 \end{array} \right]$

Row Operation 6: multiply the 3rd row by -1/15

$\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & \frac{5}{4} \\\\ 0 & 0 & 0 & 1 \end{array} \right]$

Row Operation 7: add -5/4 times the 3rd row to the 2nd row

$\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]$

Row Operation 8: add 8/3 times the 3rd row to the 1st row

$\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3} & \frac{2}{3} & 0 \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]$

Row Operation 9: add 1/3 times the 2nd row to the 1st row

$\left[ \begin{array}{cccc} 1 & 0 & \frac{9}{16} & 0 \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]$

The reduced row echelon form of the augmented matrix is

$\left[ \begin{array}{cccc} 1 & 0 & \frac{9}{16} & 0 \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]$

which corresponds to the system

$\left\begin{array}{ccccc}x_1&&+\frac{9}{16} x_3&=&0&\\&1x_2&-\frac{5}{16}x_3&=&0&\\&&0&=&1&\end{array}\right$

Equation 3 cannot be solved, therefore, the system has no solution.

7 0

4 years ago

Two numbers are in a ratio of 5:4. Their sum is 720. Find the bigger number.

alexgriva [62]

So the numbers are x and y
x:y=5:4
x/y=5/4
this means that x is worth 5 units and y is worth 4 units so
x:y=5:4, therefore it can be represented by
x:y=5z:4z
we know that they add to 720
720=5z+4z
add like terms
720=9z
divide by 9
80=z
multiply by 4
320

80=z
mutipply by 5
400

the numbers are 400 and 320

8 0

4 years ago

if a race takes 8 seconds and you get 4,000 dollars from it, how much money do you get if you do that race over and over for an

Brrunno [24]

Answer:

Step-by-step explanation:

This is how I would do it:

60-8=58

4,000 x 58=$232000

Hope this helps and pls let me know if right or wrong...if wrong srry

5 0

3 years ago

Read 2 more answers

Using the piling method, which of the following can be constructed from polygons alone and discs alone

inna [77]

Answer:

All the mentioned can be constructed with the help of piling method. But, for construction of b and d we need a point as well.

Step-by-step explanation:

a) Yes, a cube can be formed by stacking polygons. If we stack squares one upon another, then the resulting 3-D figure would be a cube.

b) Yes, a cone that does not include the point can be made by stacking disc. If we stack discs such that the discs are arranges in descending order then the resultant 3-D figure would be a cone that does not include a point.

c) Yes, a pyramid can be formed by stacking polygons.

If we stack squares such that they are arranged in descending order of their side length and stacked by a point on the top. Then the resultant figure would be a pyramid that includes a vertex.

f) There are many types of prism. Fro example a rectangular prism can be constructed by simply stacking rectangle polygon on one another.

e) Yes, a cone can be formed by stacking disc.

We need to stack disks arranged in descending order of their radius stacked with a point on the top. The resulting figure would be a cone that includes a point.

f) Yes, a cylinder can be formed by stacking. We need to stack discs of same radius to get a cylinder.

5 0

3 years ago

Read 2 more answers