Yes it is because you divide 12/7 by 3/1
The answer to this question is:
y = -2x - 1
Answer:
C. -31m⁴n - 8m²
Step-by-step explanation:
Given:
(9mn - 19m⁴n) - (8m² + 12m⁴n + 9mn)
Required:
Determine an expression equivalent to it
Solution:
(9mn - 19m⁴n) - (8m² + 12m⁴n + 9mn)
Distribute the negative sign to open the parentheses
9mn - 19m⁴n - 8m² - 12m⁴n - 9mn
Combine like terms
9mn - 9mn - 19m⁴n - 12m⁴n - 8m²
-31m⁴n - 8m²
Therefore, -31m⁴n - 8m² is an equivalent expression of (9mn - 19m⁴n) - (8m² + 12m⁴n + 9mn)
Answer:
y - 7 = -1/4(x-4)
Step-by-step explanation:
point slope is y-y₁=m(x-x₁)
(4, 7) and (8, 6)
I like to put it in the slope-intercept form first
so... 6 - 7/ 8-4 = -1/4 (slope)
6 = -1/4(8) + b
6/(-2) = -2/(-2) + b
-3 = b
so... y=-1/4x + -3
plug it in to point slope form
y - 7 = -1/4(x-4)
hopefully that made sense :)
Answer:
The sample size to obtain the desired margin of error is 160.
Step-by-step explanation:
The Margin of Error is given as

Rearranging this equation in terms of n gives
![n=\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2](https://tex.z-dn.net/?f=n%3D%5Cleft%5Bz_%7Bcrit%7D%5Ctimes%20%5Cdfrac%7B%5Csigma%7D%7BM%7D%5Cright%5D%5E2)
Now the Margin of Error is reduced by 2 so the new M_2 is given as M/2 so the value of n_2 is calculated as
![n_2=\left[z_{crit}\times \dfrac{\sigma}{M_2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{\sigma}{M/2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{2\sigma}{M}\right]^2\\n_2=2^2\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4n](https://tex.z-dn.net/?f=n_2%3D%5Cleft%5Bz_%7Bcrit%7D%5Ctimes%20%5Cdfrac%7B%5Csigma%7D%7BM_2%7D%5Cright%5D%5E2%5C%5Cn_2%3D%5Cleft%5Bz_%7Bcrit%7D%5Ctimes%20%5Cdfrac%7B%5Csigma%7D%7BM%2F2%7D%5Cright%5D%5E2%5C%5Cn_2%3D%5Cleft%5Bz_%7Bcrit%7D%5Ctimes%20%5Cdfrac%7B2%5Csigma%7D%7BM%7D%5Cright%5D%5E2%5C%5Cn_2%3D2%5E2%5Cleft%5Bz_%7Bcrit%7D%5Ctimes%20%5Cdfrac%7B%5Csigma%7D%7BM%7D%5Cright%5D%5E2%5C%5Cn_2%3D4%5Cleft%5Bz_%7Bcrit%7D%5Ctimes%20%5Cdfrac%7B%5Csigma%7D%7BM%7D%5Cright%5D%5E2%5C%5Cn_2%3D4n)
As n is given as 40 so the new sample size is given as

So the sample size to obtain the desired margin of error is 160.