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DENIUS [597]
3 years ago
8

Based on this data, what is a reasonable estimate of the probability that Nate scores 8-11 points next basketball game? Experime

ntal probability
Mathematics
1 answer:
Grace [21]3 years ago
8 0

Answer:

8/25

Step-by-step explanation:

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What is the quotient in simplest form 12/7 divided by 3?<br><br> It's 4/7 right?
raketka [301]
Yes it is because you divide 12/7 by 3/1

6 0
4 years ago
Read 2 more answers
Write an equation of the line passing through point P(0,-1) that is parallel to the line y=-2x+3
irinina [24]

The answer to this question is:

y = -2x - 1

8 0
4 years ago
Which expression is equivalent to the given polynomial expression?
ivolga24 [154]

Answer:

C. -31m⁴n - 8m²

Step-by-step explanation:

Given:

(9mn - 19m⁴n) - (8m² + 12m⁴n + 9mn)

Required:

Determine an expression equivalent to it

Solution:

(9mn - 19m⁴n) - (8m² + 12m⁴n + 9mn)

Distribute the negative sign to open the parentheses

9mn - 19m⁴n - 8m² - 12m⁴n - 9mn

Combine like terms

9mn - 9mn - 19m⁴n - 12m⁴n - 8m²

-31m⁴n - 8m²

Therefore, -31m⁴n - 8m² is an equivalent expression of (9mn - 19m⁴n) - (8m² + 12m⁴n + 9mn)

6 0
3 years ago
Help I don’t understand and I need this<br> Done as soon as possible
Sonbull [250]

Answer:

y - 7 = -1/4(x-4)

Step-by-step explanation:

point slope is y-y₁=m(x-x₁)

(4, 7) and (8, 6)

I like to put it in the slope-intercept form first

so... 6 - 7/ 8-4 = -1/4 (slope)

6 = -1/4(8) + b

6/(-2) = -2/(-2) + b

-3 = b

so... y=-1/4x + -3

plug it in to point slope form

y - 7 = -1/4(x-4)

hopefully that made sense :)

3 0
3 years ago
The daily revenues of a cafe near the university are approximately normally distributed. The owner recently collected a random s
lbvjy [14]

Answer:

The sample size to obtain the desired margin of error is 160.

Step-by-step explanation:

The Margin of Error is given as

MOE=z_{crit}\times\dfrac{\sigma}{\sqrt{n}}

Rearranging this equation in terms of n gives

n=\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2

Now the Margin of Error is reduced by 2 so the new M_2 is given as M/2 so the value of n_2 is calculated as

n_2=\left[z_{crit}\times \dfrac{\sigma}{M_2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{\sigma}{M/2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{2\sigma}{M}\right]^2\\n_2=2^2\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4n

As n is given as 40 so the new sample size is given as

n_2=4n\\n_2=4*40\\n_2=160

So the sample size to obtain the desired margin of error is 160.

4 0
4 years ago
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