Hello there!
Speed has the following formula:
S =
![\frac{D}{T}](https://tex.z-dn.net/?f=%20%20%5Cfrac%7BD%7D%7BT%7D%20%20)
, or
Speed is equivalent to
Distance divided by Time.Let's check out our problems to solve for the speed.
16.)
We have 770 miles, which is a measure of distance.
We have 120 minutes, which is a measure of time.
Let's substitute our variables with these numbers.
S =
![\frac{770}{120}](https://tex.z-dn.net/?f=%20%5Cfrac%7B770%7D%7B120%7D%20)
Simplify.
S = ~6.41 Mi/min
17.)
We have 2.5 mi, which is our measurement of distance.
We have 0.5 h, which is our measurement of time.
S =
![\frac{2.5}{0.5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2.5%7D%7B0.5%7D%20)
Simplify.
S = 5 Mph (When you divide by 0.5 you are multiplying the numerator by 2).
18.)
We have 244 km, our distance.
We have 2.5 h, our time.
S =
![\frac{244}{2.5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B244%7D%7B2.5%7D%20)
Simplify.
S = 97.6 km/h
I hope this helps!
Answer:
<u>4y = x + 13</u>
Step-by-step explanation:
The general equation of the line y = mx + c
where m is the slope and c is constant represent y-intercept
The line shown in the graph pass through the points (3,4) , (-1,3)
The slope of the line = (y₂-y₁)/(x₂-x₁) = (3-4)/(-1-3) = -1/-4 = 1/4
∴ y = (1/4) x + c
Substitute with the point (3,4) to find c
∴ 4 = (1/4) 3 + c
∴ c = 4 - 3/4 = 13/4
∴ y = (1/4) x + 13/4 ⇒ multiply both sides by 4
∴ 4y = x + 13
So, The equation of the line in the graph: 4y = x + 13
The equation can be written as <u>y = (1/4) x + 13/4 OR 4y - x = 13</u>
1,004. Take the 2006 number and subtract the 2004 number and that will be your answerz
Answer:
x = 28 y = 122
Step-by-step explanation:
Transversal Lines would be 112 and 4x
112 / 4 = 28
x = 28
y and 122 are alternate interior angles
so y = 122
hope this helps ^^
The relationship between y and x is y = 5x + 15.
<h3>
Linear equation</h3>
A linear equation is in the form:
y = mx + b
where y, x are the variables, m is the rate of change (slope) and b is the initial value of y (y intercept).
From the table, using point (5, 40) and (25, 140):
![y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-40=\frac{140-40}{25-5} (x-5)\\\\y=5x+15](https://tex.z-dn.net/?f=y-y_1%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%20%28x-x_1%29%5C%5C%5C%5Cy-40%3D%5Cfrac%7B140-40%7D%7B25-5%7D%20%28x-5%29%5C%5C%5C%5Cy%3D5x%2B15)
The relationship between y and x is y = 5x + 15.
Find out more on Linear equation at: brainly.com/question/14323743