8 because 12x8=96 and 12 inches in a foot
Answer:
-3/2 or 1.5
Step-by-step explanation:
5n + 10 = n + 4
5n - n = -10 + 4
4n = -6
n = -6/4
n = -3/2 (or -1.5)
Area of the triangle = 6x + 36
Perimeter of the rectangle = 3x + 10
<h3>How to Find the Area and Perimeter of a Triangle?</h3>
Given the following parameters of a triangle as shown in the image attached below, its area and perimeter is calculated as shown below?
Area of the triangle = 1/2(base)(height) = 1/2(12)(x + 6)
Area of the triangle = 6(x + 6)
Area of the triangle = 6x + 36
The perimeter of the triangle = sum of all the three sides of the given triangle = (x - 7) + (2x + 5) + (12)
Perimeter= x - 7 + 2x + 5 + 12
Add like terms
Perimeter= x + 2x - 7 + 5 + 12
Perimeter= 3x + 10
Therefore, we have:
Area of the triangle = 6x + 36
Perimeter of the rectangle = 3x + 10
Learn more about the area and perimeter of a rectangle on:
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Answer:
the sky is up :D
Step-by-step explanation:
Area of a square is defined as
Area = (side)^2
Let's start with square p. Square p has area = 17cm^2
Plug 17cm^2 into our area formula
17cm^2 = (side)^2. Take the square root of each side.
Sqrt(17) cm = side.
Every side for square p = sqrt(17) cm.
Next, square R has an area of 50 cm^2. Plug that into our formula.
50 cm^2 = (side)^2. Take the square root of each side.
Sqrt(50) = side.
Every side for square R = sqrt(50)
We now have one leg and the hypotenuse of a right triangle. Plug this into the pythagorean theorem.
b is the length of a side for square Q
(Sqrt(17))^2 + b^2 = (sqrt(50))^2. Square every term.
17 + b^2 = 50. Subtract 17 from both sides.
b^2 = 33. Take the square root of each side.
b = sqrt(33)
Each side of square Q = sqrt(33).
Plug sqrt(33) into our area formula.
A = (sqrt(33))^2. Solve for A
A = 33.
The area of square Q = 33 square centimeters.