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3 years ago

Solve this problem y=.01(x-50)2 +30

Mathematics

1 answer:

wolverine [178]3 years ago

6 0

Answer: x = 5y - 100

Step-by-step explanation:

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Find m∠DEA if m∠DEA= x + 30, m∠AEF= x + 132, and m∠DEF= 146 degrees

nevsk [136]

The numerical sum of the degree measures of m ∠DEA and m ∠AEF and m ∠DEF is 360°; The numerical measures of the angles is,

m ∠DEA = 56°

m ∠AEF = 158°

m ∠DEF = 146°

Based on the given data,

m ∠DEA= x + 30,

m ∠AEF= x + 132, and

m ∠DEF= 146 degrees

If the sum of two linear angles is 360° then, they are known as supplementary angles.

∠A + ∠B + ∠C = 360°, (∠A and ∠B and ∠C are linear angles.)

So,

We can write,

m ∠AEF + m ∠DEA + m ∠DEF = 360°

( x + 132) + (x + 30) + 146 = 360°

x + 30 + x + 132 + 146 = 360°

2x + 308 = 360°

2x = 360° - 308

x = 52/2

x =26

Now, we will substitute the value of x = 26° in the ∠DEA and ∠AEF, hence we get:

m ∠DEA = x + 30

m ∠DEA = 26 + 30

m ∠DEA = 56 degrees

Also,

m ∠AEF = x + 132

m ∠AEF = 26 + 132

m ∠AEF = 158

Hence,

m ∠DEA + m ∠AEF + m ∠DEF = 360°

56 + 158 + 146 = 360°

360° = 360°

Therefore,

Therefore, the numerical sum of the degree measures of m ∠DEA and m ∠AEF and m ∠DEF is 360°; The numerical measures of the angles is,

m ∠DEA = 56°

m ∠AEF = 158°

m ∠DEF = 146°

To learn more about information visit Supplementary angles :

brainly.com/question/17550923

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The key on a pictograph tells what each picture stands for.

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3 years ago

What is the maximum number of real distinct roots that a quartic equation can have?

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An nth degree polynomial can have as many as n real roots.

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3 years ago

Cant solve this please help me 9x-2y=8 Y=2x+1

ki77a [65]

Substitute 2x+1 where y is in the equation:

9x-2(2x+1)=8

Then distribute the -2(2x+1)

9x-4x+2=8

Then combine like terms (the x)

5x+2=8

Then do -2 on both side of the equation sign

5x+2=8
- 2 -2

Then you'd get

5x=6

Then divide 5 on both sides

X= 1.2

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2 years ago

Read 2 more answers

the coordinates of the endpoints of AB are A (-8, -2) and B(16,6). Point P is on AB what are the coordinates of point P such tha

garri49 [273]

We have that
A (-8, -2) and B(16,6)

step 1
find the distance AB in the x coordinates
dABx=(16-(-8))-----> 24 units

step 2
find coordinate x of P (Px)
Px=Ax+(3/5)*dABx------> Px=(-8)+(3/5)*24----> 6.4

step 3
Find the distance AB in the y coordinates
dABy=(6-(-2))-----> 8 units

step 4
find coordinate y of P (Py)
Py=Ay+(3/5)*dABy------> Py=(-2)+(3/5)*8----> 2.8

the coordinates of P are (6.4,2.8)

see the attached figure

6 0

3 years ago