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sp2606 [1]
3 years ago
9

Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.

Mathematics
1 answer:
Mademuasel [1]3 years ago
7 0

hyh8nyuiuhn8uhhhhhhhhhhhhhhhhioh7888888888888888888888888888888yyiiiiiiiiiiiihhiuhuhhhhhhiiiiiiiiiiiiyyyyyyyyyyyyyhygyhyhyhyhyhyhyhyu hj jbbvjhgvhgvvgbjhgvgc hgcvjgvbtyfcvftugbdctxekjn hxdrrrrrrrrrrrrrrrrcfnk    gfdxrrrrrrtkj nxdsrttttttttttedttttvfcccccccccctggggggggggggggggggggggggb

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if you subtract 17 from my number and multiply the difference by -6 the results is -138 what is Sarah's number
likoan [24]

Answer:

40

Step-by-step explanation:

let the unknown be y (x is used as times(multiplication) )

(y-17)x-6=-138

add /-6 to both sides

y-17x-6/-6=-138/-6

y-17=23

make y independent/add 17 to both sides

y-17+17=23+17

y=40

or in an easier way

-138/-6 =23

23+17=40

simply reversing the question to get the answer

7 0
3 years ago
Tim and Tom are painters. Tim and Tom use a liters of paint on a large shipping crate. If the next crate they need to paint is s
antiseptic1488 [7]
This is the concept algebra.
Volume of of paint that is required to paint  large shipping crate is a liters.
suppose the volume of this crate is x cubic units.
The volume of the next crate to be painted will be 2x cubic units.
Hence the amount of paint required to paint the crate will be:
(volume of bigger crate)/(volume of smaller crate)×(volume of liters required to paint the first crate)
=(2x)/(x)×a
=2a liters
To paint the new crate 2a liters of oil is needed.
5 0
3 years ago
Helppppp meeeee. Plzzzzz it’s due in 5 minutes and is half my grade:(((((((((;(((((((
sergey [27]

Answer:

5 millimeters

Step-by-step explanation:

the conversion rate from cm to mm is 1 to 10 so 0.5 would equal to 5 mil

it would be amazing if you marked this brainliest :)

6 0
3 years ago
The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Fin
NISA [10]

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, \mu=8.04 g

Standard deviation, \sigma=0.08g

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of  machine components

P(Xx_2)=0.03

P(X

=0.03

From z- table we get

P(Z1.88)=0.03

Therefore, we get

\frac{x_1-8.04}{0.08}=-1.88

x_1-8.04=-1.88\times 0.08

x_1=-1.88\times 0.08+8.04

x_1=7.8896

\frac{x_2-8.04}{0.08}=1.88

x_2=1.88\times 0.08+8.04

x_2=8.1904

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

5 0
2 years ago
tana fills the prism shown (3 1/4 and 4 inch) with 110 1/2 in squared of liquid what is the height of the prism
mixas84 [53]
(X)(3.25)(4)= 110.5
4
(x)(3.25)= 27.625
3.25
x = 8.5
(8.5)(3.25)(4)= 110.5
5 0
3 years ago
Read 2 more answers
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