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sp2606 [1]
3 years ago
9

Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.

Mathematics
1 answer:
Mademuasel [1]3 years ago
7 0

hyh8nyuiuhn8uhhhhhhhhhhhhhhhhioh7888888888888888888888888888888yyiiiiiiiiiiiihhiuhuhhhhhhiiiiiiiiiiiiyyyyyyyyyyyyyhygyhyhyhyhyhyhyhyu hj jbbvjhgvhgvvgbjhgvgc hgcvjgvbtyfcvftugbdctxekjn hxdrrrrrrrrrrrrrrrrcfnk    gfdxrrrrrrtkj nxdsrttttttttttedttttvfcccccccccctggggggggggggggggggggggggb

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If AC = 2, CD = 6, and CE = 3, what is BC?
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Answer:

Hello,

Statement:                        Reasons:

BC/CD = AC/CE                 1. Given

∠BCA = ∠ECD                    2. Vertical ∠'s =

△ACB ~ △ECD                   3. SAS

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Step-by-step explanation:

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One third of a number t is equal to 7
Novosadov [1.4K]
7 / 1/3
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Six friends go out to lunch and decide to split the bill evenly. The bill comes to $61.56. How much does each person owe?
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7 0
3 years ago
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Please help me with this math question!
barxatty [35]
1) Change radical forms to fractional exponents using the rule:
The n<span>th root of "</span>a number" = "that number" raised to the<span> reciprocal of n.
For example </span>\sqrt[n]{3} =   3^{ \frac{1}{n} }.

The square root of 3 (\sqrt{3}) = 3 to the one-half power (3^{ \frac{1}{2} }).
The 5th root of 3 (\sqrt[5]{3}) = 3 to the one-fifth power (3^{ \frac{1}{5} }).

2) Now use the product of powers exponent rule to simplify:
This rule says a^{m} a^{n} = a^{m+n}&#10;. When two expressions with the same base (a, in this example) are multiplied, you can add their exponents while keeping the same base.

You now have (3^{ \frac{1}{2} })*(3^{ \frac{1}{5} }). These two expressions have the same base, 3. That means you can add their exponents:
(3^{ \frac{1}{2} })(3^{ \frac{1}{5} })\\&#10;= 3^{(\frac{1}{2} + \frac{1}{5}) }\\&#10;= 3^{\frac{7}{10}}

3) You can leave it in the form 3^{\frac{7}{10}} or change it back into a radical \sqrt[10]{3^7}

------

Answer: 3^{\frac{7}{10}} or \sqrt[10]{3^7}
6 0
3 years ago
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