Using Pythagoras theorem, the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.
Let distance from the wall to the foot of the ladder is 'x' feet and the height of the top of the ladder is 'y' feet.
Pythagoras theorem,
--->(1)
Given,
at x=3
Put x=3 in Pythagoras theorem equation (1)


= 135
y = 11.61
Derive equation (1) w.r.t to 't'
---->(2)
substitute the value of 'x', 'dx/dt' and 'y' in equation (2), we get the fast of the top of the ladder moving down when the foot of the ladder is 3 feet from the wall
12 + 23.22
= 0


Hence, using Pythagoras theorem the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.
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Answer:
$13.91
Step-by-step explanation:
$83.48 : 6 hours
$X : 1 hour
X/1 = 83.48/6
X = 13.91333333
D I think is the answer because it’s the first on I looked at
Quotient of a decimal and a whole number"
0.2 / 5 = 0.04
Answer:
10 miles per hour.
Step-by-step explanation:
Let x represent athlete's walking speed.
We have been given that her jogging rate is 5 mph faster than her walking rate, so athlete's jogging speed would be
miles per hour.

10 minutes = 1/6 hour.
20 minutes = 1/3 hour
While walking, we will get 

While jogging, we will get 

Since athlete is covering same distance while walking and jogging, so we can equate both expressions as:

Cross multiply:




Therefore, athlete's walking speed is 5 miles per hour.
Jogging speed: 
Therefore, athlete's jogging speed is 10 miles per hour.