Cannot be determined as there isn’t an angle
Answer:
V = 128π/3 vu
Step-by-step explanation:
we have that: f(x)₁ = √(4 - x²); f(x)₂ = -√(4 - x²)
knowing that the volume of a solid is V=πR²h, where R² (f(x)₁-f(x)₂) and h=dx, then
dV=π(√(4 - x²)+√(4 - x²))²dx; =π(2√(4 - x²))²dx ⇒
dV= 4π(4-x²)dx , Integrating in both sides
∫dv=4π∫(4-x²)dx , we take ∫(4-x²)dx and we solve
4∫dx-∫x²dx = 4x-(x³/3) evaluated -2≤x≤2 or too 2 (0≤x≤2) , also
∫dv=8π∫(4-x²)dx evaluated 0≤x≤2
V=8π(4x-(x³/3)) = 8π(4.2-(2³/3)) = 8π(8-(8/3)) =(8π/3)(24-8) ⇒
V = 128π/3 vu
Answer:
D
Step-by-step explanation:
To obtain f(g(x)) substitute x = g(x) into f(x), that is
f(10 - 5x)
= (10 - 5x)² + 5 ← expand (10 - 5x)²
= 100 - 50x - 50x + 25x² + 5 ← collect like terms
= 25x² - 100x + 105 → D
Well here's the equation 4x3 x2=24 for both of the sides and the top 10x2 because if 4 is the bottom and the sides are 6 6-4=2 so 10x2=20 and we add the areas and
<u><em>20</em></u>
<u><em>+</em></u>
<u><em>24</em></u>
_____
44 is the combined areas (Your answer 44)
HOPE THIS HELPS :D
It should be zero solutions since the lines never intersect.
I mean it could also be viewed as if they intersect at every point so I'm sorry if its wrong (the M is slightly above the N so it should be parallel)
Its perpendicular if it only intersected at one point- 1 solution
If it intersects at every point- infinitely many solutions
