<h2>
The first term of the given sequence (a) = 6561</h2>
Step-by-step explanation:
Let the first term = a and common difference = d
Given,
= 729 and
= 243
To find, the first term of the given sequence (a) = ?
We know that,
The nth term of a G.P.

The 3rd term of a G.P.

⇒
= 729 ..............(1)
The 4th term of a G.P.

⇒
= 243 ..............(2)
Dividing equation (2) by (1), we get
=
⇒ 
Put
in equation (1), we get
= 729
⇒
= 729
⇒ a = 9 × 729 = 6561
∴ The first term of the given sequence (a) = 6561
3x-8=-3+2x
x-8=-3
x=5
the number is 5 hope this helped (:
The answer is 3.15 rounded to the hundredths.
By using the calculator, log 6 = 0.7781...
log 60,000 is just equal to log (6 * 10,000)
log (6 * 10,000) = log 6 + log 10,000
As we know that log 10 = 1, log 100 = 2, log 1000 = 3, and so on.
So log 10,000 = 4
Going back to our equation,
log (6 * 10,000) = log 6 + log 10,000
log 60,000 = 0.7781 + 4
So log 60,000 = 4.7781