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Stolb23 [73]
3 years ago
10

mrs. li bought some crackers. she gave 30% of the crackers to her neighbor and ate 50% of the remaining crackers. mrs. li had 42

crackers left. how many crackers did mrs. li buy?
Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0
<u><em>Answer:</em></u>
She bought 120 crackers

<u><em>Explanation:</em></u>
Assume that the number of crackers she originally bought was x

We know that she gave her neighbor 30% of the crackers.\This means that:
amount left with her = x - 30%x
amount left with her = x - 0.3 x
amount left with her = 0.7x crackers

Now, we know that she ate 50% of that amount.
This means that:
she ate 50%(0.7x) = 0.5(0.7x) = 0.35x crackers
amount left with her = 0.7x - 0.35x = 0.35x crackers 

<u>Finally,</u> we know that the number of crackers left with her is 42 crackers.
<u>This means that:</u>
0.35x = 42
x = \frac{42}{0.35}
x = 120 crackers

Hope this helps :)
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Two terms in a geometric sequence are a3=729 and a4=243.
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Step-by-step explanation:

Let the first term = a and common difference = d

Given,

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To find, the first term of the given sequence (a) = ?

We know that,

The nth term of a G.P.

a_{n} =ar^{n-1}

The 3rd term of a G.P.

a_{3} =ar^{3-1}

⇒ ar^{2} = 729          ..............(1)

The 4th term of a G.P.

a_{4} =ar^{4-1}

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Dividing equation (2) by (1), we get

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