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2 years ago

8. Line passes through the points (-6, 6) and (2, -6)

Mathematics

1 answer:

Hoochie [10]2 years ago

7 0

Slope = change in y over change in x:

Slope = (-6 6) / 2- -6) = -3/2

Equation of a line is y = Mx + b, where m is the slope and b is the y intercept.

Y = -3/2x + b

Replace y and x with one of the given points and solve for b:

6 = -3/2(-6) + b

6 = -9 + b

B = -9 + 6

B = -3

The equation of the line is y = -3/2x-3

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Find the surface area of a square pyramid with base edges<br> of 5 cm and a slant height of 3 cm.

ch4aika [34]

Answer:

Surface area of square pyramid = $55cm^{2}$

Step-by-step explanation:

Let, b is the base edges and s is the slant height

According to given condition:

b = 5 cm

s = 3 cm

Find out:

Surface area of square pyramid = ?

Formula:

Surface area of square pyramid = $b^{2} + 2bs$

Solution:

Surface area of square pyramid = $b^{2} + 2bs$

Surface area of square pyramid = $5^{2} + 2(5)(3)$

Surface area of square pyramid = $(25+ 30 ) cm^{2}$

Surface area of square pyramid = $55cm^{2}$

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3 years ago

URGENT WILL GIVE BRAINLIEST

ExtremeBDS [4]

Answer:

Step-by-step explanation:

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2 years ago

Write the first five digits of 1/7 in base 9 expression

kaheart [24]

Compare 1/7 to consecutive multiples of 1/9. This is easily done by converting the fractions to a common denominator of LCM(7, 9) = 63:

1/9 = 7/63

2/9 = 14/63

while

1/7 = 9/63

Then 1/7 falls between 1/9 and 2/9, so 1/7 = 1/9 plus some remainder. In particular,

1/7 = 1/9¹ + 2/63.

We do the same sort of comparison with the remainder 2/63 and multiples of 1/9² = 1/81. We have LCM(63, 9²) = 567, and

1/9² = 7/567

2/9² = 14/567

3/9² = 21/567

while

2/63 = 18/567

Then

2/63 = 2/9² + 4/567

1/7 = 1/9¹ + 2/9² + 4/567

Compare 4/567 with multiples of 1/9³ = 1/729. LCM(567, 9³) = 5103, and

1/9³ = 7/5103

2/9³ = 14/5103

3/9³ = 21/5103

4/9³ = 28/5103

5/9³ = 35/5103

6/9³ = 42/5103

while

4/567 = 36/5103

so that

4/567 = 5/9³ + 1/5103

and so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/5103

Next, LCM(5103, 9⁴) = 45927, and

1/9⁴ = 7/45927

2/9⁴ = 14/45927

while

1/5103 = 9/45927

Then

1/5103 = 1/9⁴ + 2/45927

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/45927

One last time: LCM(45927, 9⁵) = 413343, and

1/9⁵ = 7/413343

2/9⁵ = 14/413343

3/9⁵ = 21/413343

while

2/45927 = 18/413343

Then

2/45927 = 2/9⁵ + remainder

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/9⁵ + remainder

Then the base 9 expansion of 1/7 is

0.12512..._9

8 0

2 years ago

Which statement is true about the number of faces on any prism?

antiseptic1488 [7]

<span>B. It is the number of edges on one base plus 2.</span>

7 0

3 years ago

How can I create a sine graph that has a period of 2π and an amplitude of 3?

inna [77]

Hello!

The parent function of the graph of sin is y = sin(x).

Amplitude is the maximum displacement on the graph of a function.

Period is the displacement of x at which the graph of a function begins to repeat.

The period can be found by using the formula: $P = \frac{2\pi}{B}$ .

Since the amplitude is 3, the graph of sin is y = 3sin(x).

Given the period 2π, we can substitute this value into the given formula, $P = \frac{2\pi}{B}$ , to find B.

2π = 2π / B (multiply B to both sides)

2π · B = 2π (divide by 2π)

B = 1

Thus, the equation is y = 3sin(x). I'll post the graph as well.

6 0

3 years ago