$6x^2-x=2\implies 6x^2-1x-2=0 \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{6}x^2\stackrel{\stackrel{b}{\downarrow }}{-1}x\stackrel{\stackrel{c}{\downarrow }}{-2}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}$

$x = \cfrac{ -(-1) \pm \sqrt { (-1)^2 -4(6)(-2)}}{2(6)}\implies x = \cfrac{1\pm\sqrt{1+48}}{12} \\\\\\ x = \cfrac{1\pm\sqrt{49}}{12}\implies x = \cfrac{1\pm 7}{12}\implies x = \begin{cases} \frac{8}{12}\to &\frac{2}{3}\\[1em] -\frac{6}{12}\to &-\frac{1}{2} \end{cases}$

7 0

3 years ago

Mia is tracking her savings account balance . She knows the equation to find her balance y in any year t, but she can't remember

motikmotik

Complete question is;

Mia is tracking her savings account balance. She knows the equation y = 8000p^(t) can be used to find her balance y in any year t, but she can't remember what p represents. Her balance 3⅔ years after opening her account, is $9,905.54. What is the value of p?

Answer:

p = 1.06

Step-by-step explanation:

We are told that the equation y = 8000p^(t) can be used to find her balance y in any year t.

Now, we are given t = 3⅔ = 11/3 years

Also, we are given balance after 11/3 years as;

y = $9,905.54

Thus;

Plugging the relevant values into y = 8000p^(t), we have;

9,905.54 = 8000p^(11/3)

p^(11/3) = 9905.54/8000

p = (9905.54/8000)^(3/11)

p = 1.06

4 0

4 years ago

One subtracted by negative three

timama [110]

-2 you just subtract the 3 by 1

8 0

4 years ago

Read 2 more answers

X = 4 and y = 3. 3x 2 + 5y A. 27 B. 31 C. 63 D. 159

ryzh [129]

Answer:

Step-by-step explanation:

I did the math

8 0

3 years ago