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labwork [276]
3 years ago
14

The average of four numbers is 98. If three of those numbers are 86, 87, and 91, what is the fourth number?

Mathematics
2 answers:
Alinara [238K]3 years ago
7 0

~Hello There!~

86 + 87 + 91 = 264

98 x 4 = 392

392 - 264 = 128

The fourth number is 128

Hope This Helps You!

Good Luck :)

Have A Great Day ^_^

- Hannah ❤

BabaBlast [244]3 years ago
4 0

Answer:

128

Step-by-step explanation:

86 plus 87 plus 91 =264  

You have to get 98 times 4 which is 392  

Then;

392-264, which is 128, which is the answer (the fourth number)  

So;

86+87+91+128 = 392 divided by 4 (the number of numbers there is) which equals 98!  

Hope it helped

Please mark me as Brainliest

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2) help ASAP due in like 10min
Anna [14]

Answer:

y=25x-5

Step-by-step explanation:

25x is the money you start with and 5 is a constant that you lose per game hence the negative/or subtraction sign

Branliest plsssss

8 0
3 years ago
(Algebra II ) What is the equation of y = x^3 with the given transformations? vertical compression by a factor of 1/7, horizonta
NNADVOKAT [17]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\

\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\mathbb{R}^{{{  B}}x+{{  C}}}+{{  D}}
\end{array}  \bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\
\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}
\end{array}

\bf ----------------------------\\
f(x)=x^3\textit{compression by }\frac{1}{7}\quad or\quad A=7
\\ \quad \\
f(x)=7x^3\impliedby \textit{8 units to the left, or }C=+8
\\ \quad \\
f(x)=7(x+8)^3\impliedby \textit{now, reflection over x-axis, means}
\\ \quad \\
f(x)=-7(x+8)^3\impliedby \textit{a negative leading term's coefficient}
6 0
3 years ago
What is the right answer?
scZoUnD [109]

Answer:

The answer is 34

Step-by-step explanation:

so you need to fine out the value of x  

6 0
3 years ago
I need to help with that
Bingel [31]
The ratio of people that can be served to milligrams of baking soda needed is:

Serving : Baking Soda
2 : 1600mg

Since you want 10 people, you can multiply this ratio by 5:5 to get 

10 people served = 8000mg needed

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3 0
3 years ago
If you have 6 cars, but there is only room in your driveway for 3 cars, in how many ways can you arrange the cars in your drivew
Svetradugi [14.3K]

If the order does not matter, cars can be arranged in 20 ways

If an order is important, cars can be arranged in 120 ways

The probability that the three newest cars end up parked in the driveway is 0.167

1. If the order does not matter, combination is used

\left ({n} \atop {r}} \right.)=\frac{n!}{r!(n-r)!}

Here, n=6 r=3

using formula,we get

\left ( {{6} \atop {3}} \right)=\frac{6!}{3!3!} =5*4=20

2. If an order is important, Permutation will be applicable

^{n}P_{r} = \frac{n!}{(n-r)!} \\

∴^{6} P_{3} =\frac{6!}{3!(6-3)!}=\frac{6!}{3!}  =120

3. the probability that the three newest cars end up parked in the driveway

P=\frac{No. of possible outcomes for 3 cars}{total possibilities}

=\frac{6*4*5}{6!}

=\frac{120}{720}

=\frac{1}{6} ≈ 0.167

Hence, If the order does not matter, cars can be arranged in 20 ways

If an order is important, cars can be arranged in 120 ways

The probability that the three newest cars end up parked in the driveway is 0.167

Learn more about probability here brainly.com/question/6077878

#SPJ4

7 0
2 years ago
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