Question

Use the Special Right Triangle to evaluate sin 60°, cos 60° and tan 60°. Your answers should be exact (not a decimal).

Answer 1

Sin 60 = $\sqrt{3}$/2
cos 60 = 1/2
tan 60 = $\sqrt{3}$

The answer to your question is D. I hope that this is the answer that you were looking for and it has helped you.

Answer 2

Answer:

The correct option is:  Option: D

  D. sin 60 = √3/2, cos 60 = 1/2, tan 60 = √3

Step-by-step explanation:

We will draw a right angled triangle with one angle as 60° and the length of the side adjacent to 60° be 1 units and let the hypotenuse of the triangle be 2 units.

Then by using Pythagorean Theorem we get the other leg of the triangle i.e. leg opposite to 60° will be of  length √3 units.

Since,

$2^2=1^2+b^2\\\\4-1=b^2\\\\\\b^2=3\\\\\\i.e.\\\\\\b=\sqrt{3}\ units$

We know that in a right angled triangle with one angle as θ, the trignometric ratio corresponding to θ  is given by:

$\sin \theta=\dfrac{opposite\ side}{Hypotenuse}\\\\\\\cos \theta=\dfrac{adjacent\ side\ or\ base}{Hypotenuse}\\\\\\\tan \theta=\dfrac{opposite\ side}{adjacent\ side\ i.e.\ base}$

Hence, we get:

$\sin \theta=\dfrac{\sqrt{3}}{2}\\\\\\\cos \tehta=\dfrac{1}{2}\\\\\\\tan \theta=\sqrt{3}$