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3 years ago

Find the value of the expression 4d divided by c +3 when c=3 and d = 6

Mathematics

2 answers:

statuscvo [17]3 years ago

7 0

What I got:

11

Explanation:

4d / c+3

4 x 6 = 24

24 / 3 + 3

24/3 = 8

8+3= 11

Sav [38]3 years ago

5 0

$\text{Given that, c=3, d=6}\\\\\dfrac{4d}{c+3} = \dfrac{4(6)}{3+3} = \dfrac{4(6)}6 = 4$

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Jonathan buys two baseball bats for $43 each they are on sale for 45% off he also bought a glove that was originally priced at 2

vladimir2022 [97]

Hi There!

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Baseball Bats:

43 x 0.45 = $19.35 as the amount off.

43 - 19.35 = $23.65 with the discount.

23.65 x 2 = $47.3 for two bats.

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Glove:

28 x 0.25 = $7 as the amount off.

28 - 7 = $21 with the discount.

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Together:

21 + 47.3 = $68.3 as the total before taxes.

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With Taxes:

68.3 x 0.055 = $3.7565 as the tax amount.

68.3 - 3.7565 = $64.5435

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Answer:

Not Rounded: $64.5435

Rounded: $64.54

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Hope This Helps :)

3 0

3 years ago

12/21 in its simplest form

UNO [17]

12/21 in its simplest form is 4/7.

To find this out we need to divide the numerator and denominator by the GCF of 12 and 21 which is 3.

12/21

12 ÷ 3 = 4
21 ÷ 3 = 7
4/7

12/21 in its simplest form is 4/7.

12/21 = 4/7

5 0

3 years ago

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lorasvet [3.4K]

Answer:

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Step-by-step explanation:

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3 years ago

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What is the volume of a cylinder with base radius 2 and height 6?

DaniilM [7]

Answer:

75.4

Step-by-step explanation:

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3 years ago

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A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago