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scoundrel [369]
3 years ago
11

Robert climbs 775 steps in 12 1/2 minutes what was his average steps per minute

Mathematics
1 answer:
mart [117]3 years ago
7 0
775 steps divided by 12.5. minutes is 62 so his average steps per minute is 62 steps per minute
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Help with this question thx
mario62 [17]

Answer:

3.5ft

Step-by-step explanation:

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3 years ago
PLEASE HELP ME I WILL GIVE BRAINLIEST!!!
Svet_ta [14]

Answer:

Step-by-step explanation:

realtionship between distance and time is

distance=time/3

a.distance=time/3

129*3=time

387 s =time

7 0
2 years ago
Read 2 more answers
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
bezimeni [28]

Answer:

See explanation and results below.

Step-by-step explanation:

We have the following data:

Age​ (yr) when award was won Frequency 25​-34 31 35​-44 36 45​-54 12 55​-64 4 65​-74 6 75​-84 1 85​-94 2

If we order the data we got the following result. We assume that the midpoint is given by:

Midpoint= \frac{L.Limit +U.Limit}{2}

The Class.Width = U.Limit-L.Limit

And the limits are given by the lower and upper limit.

L.Limit  U.Limit Class W  Midpoint  Frequency   Limits

  25         34     34-25=9     29.5           31           [25-34]                

  35         44      44-35=9     39.5          36           [35-44]

  45         54      54-45=9     49.5           12           [45-54]

  55         64      64-55=9     59.5           4            [55-64]

  65         74       74-65=9     69.5           6            [65-74]

  75          84      84-75=9     79.5            1            [75-84]

  85          94      94-85=9     89.5           2           [85-94]

8 0
3 years ago
The sum of two numbers is 28 and there quotient is 3 what are the numbers
Zepler [3.9K]
54 and 21 and thats how i got it lol
5 0
3 years ago
If alpha beta are the roots of the equation
Vikki [24]

Answer:

Step-by-step explanation:

Hello, I believe that we can consider a different from 0.

By definition of the roots we can write.

ax^2+bx+c=a(x-\alpha)(x-\beta)=a(x^2-(\alpha + \beta)x+\alpha \cdot \beta)\\\\\text{So we can say that:}\\\\\alpha + \beta = \dfrac{-b}{a}\\\\\alpha \cdot \beta=\dfrac{c}{a}\\\\\text{So the expected quadratic equation is}\\\\(x+\dfrac{b}{a})(x-\dfrac{c}{a})=0\\\\ \Large \boxed{\sf \bf \ (ax+b)(ax-c)=0 \ }

Thank you

8 0
2 years ago
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