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2 years ago

5

What is 0.5, 3/16, 0.75, and 5/45 from least to greatest

1 answer:

BartSMP [9]2 years ago

8 0

5/45, 3/16, 0.5, & 0.75

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Write a equation of a hyperbola given the foci and the asymptotes

professor190 [17]

Solution:

The standard equation of a hyperbola is expressed as

$\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\text{ \lparen parallel to the x-axis\rparen} \\ \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ \lparen parallel to the y-axis\rparen} \end{gathered}$

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.

Thus, the equation will be expressed in the form:

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ ----equation 1}$

The asymptote of n hyperbola is expressed as

$y=\pm\frac{a}{b}(x-h)+k$

Given that the asymptotes are

$y=\frac{3}{4}x\text{ and y=-}\frac{3}{4}x$

This implies that

$a=3,\text{ and b=4}$

To evaluate the value of h and k,

$undefined$

3 0

1 year ago

2/3x+2 -x-3 <br> solution and the steps how to do it

Stells [14]

$\text{Hey there!}$

$\mathsf{\dfrac{2}{3}x+2-x-3}\\\\\mathsf{COMBINE\ your\ like\ terms}\\\\\mathsf{(\dfrac{2}{3}x-x)+(2-3)}\\\\\mathsf{\dfrac{2}{3}x-x=\dfrac{-1}{3}}\\\\\mathsf{2-3=-1}\\\\\boxed{\boxed{Thus,\ your \ answer\ is: \boxed{\dfrac{-1}{3}x -1}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFIrst:)}$

7 0

3 years ago

Read 2 more answers

Anyone know the awnser to this?

iragen [17]

Answer:

61

Step-by-step explanation:

straight line = 180 degree

to find the measure of angle QPR,

subtract 119 from 180

=> 180-119

=> 61

angle QPR = 61 degree

6 0

2 years ago

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hi I was just a little bit of time with my module and I didn't know what is answer of the module now please please be sure of th

GREYUIT [131]

1. 5 x 4 = A. 20

2.

$\frac{2}{5} \times 25 = 2 \times 5 = 10$

the answer is D. 25

3.

$\frac{3}{5} \div 15 = \frac{3}{5} \times \frac{1}{15} = \frac{1}{5} \times \frac{1}{5} = \frac{1}{25}$

the answer is A. 1/25

4.

$4 \div \frac{1}{2} = 4 \times \frac{2}{1} = 8$

the answer is C. 8

5.

$9 \div \frac{1}{3} = 9 \times \frac{3}{1} = 27$

the answer is D. 27

6.

$20 \div \frac{1}{4} = 20 \times \frac{4}{1} = 80$

the answer is D. 80

7.

$\frac{9}{10} \div \frac{1}{2} = \frac{9}{10} \times \frac{2}{1} = \frac{18}{10} = \frac{9}{5} = 1 \frac{4}{5}$

the answer is C. 1 4/5

8.

$9 \div \frac{3}{2} = 9 \times \frac{2}{3} = \frac{18}{ 3} = 6$

the answer is B. 6

9.

$\frac{3}{4} \div \frac{3}{8} = \frac{3}{4} \times \frac{8}{3} = 2$

the answer is A. 2

3 0

2 years ago

Use f(x) = 1/2 x and f -1(x) = 2x to solve the problems. f(2) = 1 f−1(1) = 2 f−1(f(2)) = 2 f−1(−2) = f(−4) = f(f−1(−2)) =

vampirchik [111]

Answer:

In this problem, we are given the following functions:

$f(x)=\frac{1}{2}x$

and its inverse function:

$f^{-1}(x)=2x$

First of all, we want to calculate $f(2)$ . This can be obtained by substituting

x = 2

into f(x). Doing so, we find:

$f(2)=\frac{1}{2}\cdot 2 = 1$

Then we want to calculate $f^{-1}(1)$ . We can do it by substituting

x = 1

into $f^{-1}(x)$ . Doing so,

$f^{-1}(1)=2\cdot 1 = 2$

Then we want to calculate $f^{-1}(f(2))$ , which can be found by calculating f(2) and then using it as input for $f^{-1}(x).$ We know that

f(2) = 1

Therefore,

$f^{-1}(f(2))=f^{-1}(1)=2$

Then we want to calculate $f^{-1}(-2)$ , which can be calculated by plugging

x = -2

into $f^{-1}(x)$ . Doing so,

$f^{-1}(-2)=2\cdot (-2)=-4$

Then we want to calculate $f(-4)$ ; by substituting

x = 4

into f(x), we find

$f(-4)=\frac{1}{2}\cdot (-4)=-2$

Finally, we want to find $f(f^{-1}(-2))$

We know already that

$f^{-1}(-2)=-4$

So we have:

$f(f^{-1}(-2))=f(-4)=-2$

7 0

2 years ago

Read 2 more answers