1 is A, 2 is B, 4 is C, 5 is B, 6 is C, cant answer 4 bc it’s cut off
Answer:
0.27
Step-by-step explanation:
The total amount is 3.78 so to know cost of one you ➗ by 14
3.78/14=0.27
Answer:
a)120
b)6.67%
Step-by-step explanation:
Given:
No. of digits given= 6
Digits given= 1,2,3,5,8,9
Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be
6P3= 6!/3!
= 6*5*4*3*2*1/3*2*1
=6*5*4
=120
Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:
As the first and last digits can only be even
then the form of number can be
a)2n8 or
b)8n2
where n can be 1,3,5 or 9
4*2=8
so there can be 8 three-digit numbers with both the first digit and the last digit even numbers
And probability = 8/120
= 0.0667
=6.67%
The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !
Answer:5
Step-by-step explanation: you have to dived into two groups into five.
The an answer is 2x
explanation :
12+3x-x-12
= 3x-x
= 2x
