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3 years ago

8

17. A local university accepted 2,300 students out of 4,500 applicants for admission. What was the acceptance rate, expressed as

a percent?

1 answer:

pochemuha3 years ago

4 0

The acceptance rate is 51.1%

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The graph of f(x) = -2^2 was transformed to create g(x) = -(x+3)^2. Which of these describes the transformation from the graph o

mash [69]

I’m assuming you meant -2x^2 so It would be shifted to the left 3 it would be compressed from having 2 to 1.

3 0

2 years ago

Pls help ASAP and pls explain someone:)

Ivahew [28]

So we know the slope has to be -3 and the y intercept is 2. y intercept looks like (0,2). since we know this we automatically can rule out B since it has (0,0).

let’s find the slope of A
-9- -5
-3- - 1
the slope= -4/-2= 2
we know it’s not A because the slope is not -3

let’s find the slope of C
-17- -8
-5- -2
slope= -9/-3=3
we know it’s not C because the slope is not -3. we could directly assume that D is the answer no but we’ll still find the slope just to be sure

let’s find the slope of D
14-8
-4- -2
slope=6/-2= -3

the answer is D!!

8 0

3 years ago

Read 2 more answers

Fabian hikes at a rate of 3 miles per hour. how far can she home in for hours?

rjkz [21]

the answer is 12, 3x4=12

3 0

3 years ago

Find the midpoint of the segment with the given endpoints K(-2,-4) and L(-4,6)

Ilia_Sergeevich [38]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ K(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad L(\stackrel{x_2}{-4}~,~\stackrel{y_2}{6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-4-2}{2}~~,~~\cfrac{6-4}{2} \right)\implies \left( \cfrac{-6}{2}~~,~~\cfrac{2}{2} \right)\implies (-3~,~1)$

8 0

3 years ago

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If g(x)=4x^2-16 we’re shifted 9 united to the right and 1 down, what would the new equation be?

Inessa05 [86]

Shown in the graph

<h2>Explanation:</h2>

Using graph tools we can graph the function:

$g(x)=4x^2-16$

which is the red graph shown below. As you can see, this is a parabola. The rule for vertical and horizontal shifts is as follows:

$Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:$

$\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)$

Therefore, If we shift the red graph 9 units to the right and 1 down, our new function (let's call it $h(x)$ ) will be:

$h(x)=4\left(x-9\right)^{2}-16-1 \\ \\ Simplifying: \\ \\ h(x)=4\left(x-9\right)^{2}-17$

This graph is the blue graph below. Let's verify the transformation taking the vertex of the red graph:

$(0,-16)$

By translating the 9 units to the right and 1 down the vertex is also translated by the same rule, so:

$New \ vertex: \\ \\ (0+9,-16-1) \\ \\ (9,-17)$

<h2>Learn more:</h2>

Cubic function: brainly.com/question/13773618#

#LearnWithBrainly

5 0

2 years ago