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2 years ago

Which statement is true? A. .8>.79 B. .4>.40 C. .76>1.2 D. .80>.9

Mathematics

2 answers:

Hitman42 [59]2 years ago

7 0

It is A. Because .8 is the same has saying .80, it is .80>.79, and 80 is greater than 79

balandron [24]2 years ago

6 0

Answer:A

Step-by-step explanation:

0.8 is greater than 0.79 by 0.01

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Elenna [48]

Replace m with 46x10^4 in the equation and solve.

0.036(46x10^4)^3/4 = 635.87

Round to 636

The answer is A.

6 0

2 years ago

The distance traveled (d) varies directly as the time (t) of

Helen [10]

Answer:

2.70 hours to travel 180 mi.

Step-by-step explanation:

The distance traveled (d) varies directly as the time (t) of travel, by the following formula:

$s = \frac{d}{t}$

In which s is the velocity.

It takes 63 min to travel 70 mi.

So i am going to find the velocity in miles per minute

$s = \frac{70}{63} = 1.11$

how many hours would it take to travel 180 mi?

I am first going to find the time in minutes, then divide by 60 to pass to hours.

$s = \frac{d}{t}$

$st = d$

$t = \frac{d}{s}$

$t = \frac{180}{1.11}$

$t = 162.16$

It takes 162.16 minutes = 162.16/60 = 2.70 hours to travel 180 mi.

6 0

2 years ago

PQ=20,RS=20 and the measure of ARC PT= 35 Find the measure of arc RS

Oksi-84 [34.3K]

If RS arc is = to the RS central angle then the RS arc would be 20 degrees, but if the RS is on the Circumference then the RS arc would be 40.

4 0

2 years ago

Please hepl with math

Ivenika [448]

Answer:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}$

Step-by-step explanation:

We are given the expression to be simplified:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}}$

Let us take common a term with a power of 5 from the numerator and the denominator of the given expression.

We know that:

$a^{p+q} = a^p \times a^q$

Let us use it to solve the powers of 5 in the given expression.

$\therefore$ we can write:

$5^{n+2} = 5^{n+1}\times 5= 5^n\times 5^{2}$

$5^{n+1} = 5^n\times 5$

The given expression becomes:

$\dfrac{5^{n+1} \times 5-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n}\times 5}$

Taking common $5^{n+1}$ from the numerator and

Taking common $5^{n}$ from the denominator

$\Rightarrow \dfrac{5^{n+1} (5-6)} {5^{n}(13-2\times5)}\\\Rightarrow \dfrac{5^{n+1} (-1)} {5^{n}(13-10)}\\\Rightarrow -\dfrac{5^{n+1}} {5^{n}\times3}\\\Rightarrow -\dfrac{5^{n}\times 5} {5^{n}\times3}\\\Rightarrow -\dfrac{5}{3}$

$\therefore$ The answer is:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}$

6 0

2 years ago

PLS HELP ME WITH THE ANSWER <br> !!!

Sladkaya [172]

Answer: m is less than or equal to -7

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers