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katrin2010 [14]
2 years ago
13

Somebody please help me it’s due at 11:59

Mathematics
1 answer:
MakcuM [25]2 years ago
4 0

Answer:

1.24 would be the best option for your question

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Find the eighth term of an arithmetic sequence whose fourth term is 19 and whose fifteenth is 52.
Elina [12.6K]

Answer:

its C can u give me brainly

Step-by-step explanation:

3 0
3 years ago
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The ratio of 4:8 is equivalent to x:6, what is the value of x?
Dimas [21]

Answer:

x = 3

Step-by-step explanation:

Given

4 : 8 = x : 6, expressing in ratio form, that is

\frac{4}{8} = \frac{x}{6} ( cross-  multiply )

8x = 24 ( divide both sides by 8 )

x = 3

Thus 4 : 8 = 3 : 6

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3 years ago
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Whitch is the value of this expression when a=5 and k=-2
lana66690 [7]

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25/9

Step-by-step explanation:

25/9

7 0
3 years ago
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
Plz help me First right is brainliest
AysviL [449]

Answer:

20 are cows 10 chickens 20 times 4 is 80 10 times 2 equals 20 80+20=100

Step-by-step explanation:

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3 years ago
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