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3 years ago

Add one set of parenthesis to make the following equation true 25 - 8 - 2 = 19

1 answer:

7 0

An easy way to do this is to do trial and error.

All possible places to put the bracket:

a) (25 - 8) - 2 = 19 But since BEDMAS goes from left to right with Addition and Subtraction, the equation is unaffected.
b) 25 - (8 - 2) = 19
25 - 6 = 19

Therefore b) is correct.

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Someone plz help this is due today

-Dominant- [34]

3x+5x+1=17

x=2

y=5•2+1

y=1

(x, y)=(2, 11)

3x+2(4x+5)=43

x=3

y=4•3+5

y=17

(x, y)=(3, 17)

I think I did it right and I hope I helped you

3 0

2 years ago

How many minutes of calling time do the plans cost the same amount ?

Mama L [17]

D 200 minutes

.15*200 = 30+45= Plan A= $75
.25*200= 50+25= Plan B= $75

Answer is D

7 0

2 years ago

Hillside Travel pays its employees $16 per hour plus 8% commission on all trips booked. Tyrus worked 20 hours last week and book

4vir4ik [10]

Answer:

$488

Step-by-step explanation:

16×20=320

8%×2100

0.08×2100

168

320+168=$ 488

3 0

2 years ago

Suppose the roots of the polynomial $x^2 - mx + n$ are positive prime integers (not necessarily distinct). Given that $m < 20

Vsevolod [243]

Answer:

<em>18</em> values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

$x^2 - mx + n$

such that:

Roots are positive prime integers and

$m < 20$

To find:

How many possible values of $n$ are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

$Ax^{2} +Bx+C$

and the roots are: $\alpha$ and $\beta$

Then sum of roots, $\alpha+\beta = -\frac{B}{A}$

Product of roots, $\alpha \beta = \frac{C}{A}$

Comparing the given equation with standard equation, we get:

A = 1, B = -m and C = n

Sum of roots, $\alpha+\beta = -\frac{-m}{1} = m$

Product of roots, $\alpha \beta = \frac{n}{1} = n$

We are given that $m$

$\alpha$ and $\beta$ are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

2, 3, 5, 7, 11, 13, 17, 23, 29, .....

Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.

So, possible combinations and possible value of $n (= \alpha \times \beta)$ are:

$1.\ 2, 2\Rightarrow n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow n = 6\\3.\ 2, 5 \Rightarrow n = 10\\4.\ 2, 7\Rightarrow n = 14\\5.\ 2, 11 \Rightarrow n = 22\\6.\ 2, 13 \Rightarrow n = 26\\7.\ 2, 17 \Rightarrow n = 34\\8.\ 3, 3\Rightarrow n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow n = 15\\10.\ 3, 7 \Rightarrow n = 21\\$

$11.\ 3, 11\Rightarrow n = 33\\12.\ 3, 13 \Rightarrow n = 39\\13.\ 5, 5 \Rightarrow n = 25\\14.\ 5, 7 \Rightarrow n = 35\\15.\ 5, 11 \Rightarrow n = 55\\16.\ 5, 13 \Rightarrow n = 65\\17.\ 7, 7 \Rightarrow n = 49\\18.\ 7, 11 \Rightarrow n = 77$

So,as shown above <em>18 values for n are possible.</em>

3 0

2 years ago

A cable provider wants to contact customers in a particular telephone exchange to see how satisfied they are with the new digita

dusya [7]

Answer:

a) uniform

b) 1/2

c) 1/1000

Step-by-step explanation:

a) "numbers with equal probability" have a uniform distribution.

b) Even numbers make up 1/2 of all numbers.

c) There are ten such numbers in the range, so the probability is ...

10/10000 = 1/1000

7 0

3 years ago