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MA_775_DIABLO [31]

2 years ago

7

I don’t understand the question

1 answer:

kipiarov [429]2 years ago

6 0

Answer:

Answer is given below with explanations.

Step-by-step explanation:

1)

$- 13 {x}^{2} \: has \: only \: one \: term \: and \: highest \: degree \: is \: 2 \\$

1) Option d) Monomial degree 2

2)

$- 8 {y}^{7} - 3 \: has \: two \: terms \: and \: highest degree \: is \: 7$

2) Option c) Binomial degree 7

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>.</em>

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Find the perimeter of a field that has length 2/x + 1 and width 5/x^2 -1.

Semmy [17]

Answer:

D)4x + 6/(x + 1)(x - 1)

Step-by-step explanation:

A field is basically a rectangle, so to find the perimeter of our field we are using the formula for the perimeter of a rectangle

$p=2(l+w)$

where

$p$ is the perimeter

$l$ is the length

$w$ is the width

We know from our problem that the field has length 2/x + 1 and width 5/x^2 -1, so $l=\frac{2}{x+1}$ and $w=\frac{5}{x^2-1}$ .

Replacing values:

$p=2(l+w)$

$p=2(\frac{2}{x+1} +\frac{5}{x^2-1})$

Notice that the denominator of the second fraction is a difference of squares, so we can factor it using the formula $a^2-b^2=(a+b)(a-b)$ where $a$ is the first term and $b$ is the second term. We can infer that $a=x^2$ and $b=1^2$ . So, $x^2-1=(x+1)(x-1)$ . Replacing that:

$p=2(\frac{2}{x+1} +\frac{5}{x^2-1})$

$p=2(\frac{2}{x+1} +\frac{5}{(x+1)(x-1})$

We can see that the common denominator of our fractions is $(x+1)(x-1)$ . Now we can simplify our fraction using the common denominator:

$p=2(\frac{2(x-1)+5}{(x+1)(x-1)} )$

$p=2(\frac{2x-2+5}{(x+1)(x-1)} )$

$p=2(\frac{2x+3}{(x+1)(x-1)} )$

$p=\frac{4x+6}{(x+1)(x-1)}$

We can conclude that the perimeter of the field is D)4x + 6/(x + 1)(x - 1).

3 0

3 years ago

Step 1: pick a number

Bogdan [553]

If I pick n, it becomes 50(2n+5)+1764-2001 this is the expression

7 0

2 years ago

Jenny multiplies the square root of her favorite positive integer by $\sqrt{2}$. Her product is an integer. a) Name three number

Dmitry [639]

Answer:

Part a) $2,50,18$

Part b) When Jenny divides the square root of her favorite positive integer by $\sqrt{2}$ , she gets an integer

Step-by-step explanation:

Let

x-------> the favorite positive integer

Part a)

1) For $x=2$

$\sqrt{2}*\sqrt{2}=\sqrt{4}=2$ -----> the product is an integer

so

The number $x=2$ could be Jenny favorite positive integer

2) For $x=50$

$\sqrt{50}*\sqrt{2}=\sqrt{100}=10$ -----> the product is an integer

so

The number $x=50$ could be Jenny favorite positive integer

3) For $x=18$

$\sqrt{18}*\sqrt{2}=\sqrt{36}=6$ -----> the product is an integer

so

The number $x=18$ could be Jenny favorite positive integer

Part B)

1) For $x=2$

$\sqrt{2}/\sqrt{2}=\sqrt{1}=1$ -----> the result is an integer

2) For $x=50$

$\sqrt{50}/\sqrt{2}=\sqrt{25}=5$ -----> the result is an integer

3) For $x=18$

$\sqrt{18}/\sqrt{2}=\sqrt{9}=3$ -----> the result is an integer

Therefore

When Jenny divides the square root of her favorite positive integer by $\sqrt{2}$ , she gets an integer

4 0

2 years ago

Please help! Thank you

Temka [501]

Answer:

b. the radio of feet to inches

4 0

2 years ago

Somebody please help me answer part a and Part B

Pie

Part A:
6 2/3 *3 1/2 = 4 1/4 * x

Part B:
20/3 * 7/2 = 17/4 *x
x=20/3 * 7/2 * 4/17
x=(20*7*4) / (3*2*17)
x=560 / 102
<span>x= 5 25/51</span>

5 0

2 years ago